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2 years ago

Question po

Mathematics

1 answer:

Evgen [1.6K]2 years ago

3 0

nothing is no longer be available for the vitamin

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PLEASE HELP ME ON THESE QUESTIONS!!!

jasenka [17]

For Question 1 the answer is the last choice.

5 0

3 years ago

The night watchman in a factory cannot guard both the safe in back and the cash register in front. The safe contains $6000, whil

Zolol [24]

Answer:

The guard should be positioned at the safe

Step-by-step explanation:

The night watchmen should be positioned to guard whichever place gives the highest expected value to the thief.

The expected value of robbing the safe is:

$EV_{s} = \$ 6000*0.2\\EV_{s} = \$ 1200$

The expected value of robbing the cash register is:

$EV_{r} = \$ 1000*0.8\\EV_{r} = \$ 800$

Therefore, the guard should be positioned at the safe since it yields a higher expected value to the thief in case he tries to rob it.

7 0

3 years ago

When the scale factor between two circles is “x” the scale factor between the 1_________________________is also “x” and the scal

Effectus [21]

Answer:

When the scale factor between two circles is “x” the scale factor between the radius is also “x” and the scale factor of the area is “x^2"

this is only one possible answer. For example, instead of radius, you could have put diameter or circumference.

7 0

2 years ago

I am making hamburgers that are 3/4 pounds each. If I have 30 pounds of Hamburg, what fraction of hamburger do I have left.

erma4kov [3.2K]

Answer:

1/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected

valina [46]

Answer:

$\frac{7}{12}$

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

$B_1,B_2$ denote the two boxes.

In box $B_1$ :

No. of black balls = 1

No. of white balls = 1

In box $B_2$ :

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes $B_1,B_2$ is chosen is $\frac{1}{2}$

Probability that a black ball is chosen from box $B_1$ = $\frac{1}{2}$

Probability that a black ball is chosen from box $B_2=\frac{2}{3}$

To find:probability that the marble is black

Solution:

Probability that the marble is black = $\frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}$

6 0

3 years ago