An equation of the line passing through (6,−3) having slope −35 is

1 answer:

3 0

If your given slope is - 35, your equation starts off as y = - 35x + b

Now we plug in the point given and solve for b.

- 3 = - 35(6) + b
- 3 = - 210 + b
207 = b

So your equation is:
y = - 35x + 207

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Option A

The solution is $(0, \frac{-1}{4})$

Solution:

Given system of equations are:

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

We have to find solution to system of equations

We can use substitution method

From eqn 2,

x = 1 + 4y -------- eqn 3

Substitute eqn 3 in eqn 1

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cluponka [151]

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Answer:

-13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

$\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}$