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katrin [286]
3 years ago
10

Find the zeros of the function.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(x - 2)(3x + 3) = 0

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

3x + 3 = 0 ( subtract 3 from both sides )

3x = - 3 ( divide both sides by 3 )

x = - 1

Hence

smaller x = - 1

larger x = 2

docker41 [41]3 years ago
5 0

Step-by-step explanation:

• <em><u>To</u></em><em><u> </u></em><em><u>find</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>Zero</u></em><em><u>s</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>funct</u></em><em><u>ion</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>equate</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>function</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>here</u></em><em><u> </u></em><em><u>g</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>zero</u></em><em><u> </u></em>

<em>=</em><em>></em><em> </em><em><u>g</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>)</u></em>

<em>g</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em>(</em><em> </em><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>either</em><em> </em><em>,</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>OR</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>OR</em><em> </em><em>3</em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>)</em>

<em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>OR</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em>

<em>•</em><em> </em><em>Smaller</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em>

<em>•</em><em> </em><em>Larger</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em>

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