All categories

3 years ago

Find the zeros of the function.

Mathematics

2 answers:

Slav-nsk [51]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(x - 2)(3x + 3) = 0

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

3x + 3 = 0 ( subtract 3 from both sides )

3x = - 3 ( divide both sides by 3 )

x = - 1

Hence

smaller x = - 1

larger x = 2

docker41 [41]3 years ago

5 0

Step-by-step explanation:

• To find the Zeros of the function we equate the function ( here g ( x ) ) by zero

=> g ( x ) = ( x - 2 ) ( 3x + 3 )

g ( x ) = 0

( x - 2 ) ( 3x + 3 ) = 0

either , ( x - 2 ) = 0 OR ( 3 x + 3 ) = 0

x = 2 OR 3x = ( - 3 )

x = 2 OR x = ( - 1 )

• Smaller x = ( - 1 )

• Larger x = 2

You might be interested in

Use the interactive to graph the line that goes through

il63 [147K]

Answer:

The correct answer with step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the volume of a hemisphere with a radius of 4.9 ft, rounded to the nearest

Alexxx [7]

Answer:

Step-by-step explanation:

To round 4.9 to nearest tenth means to round the numbers so you only have one digit in the fractional part. 4.9 already has only one digit in the fractional part. Thus, 4.9 is already rounded as much as possible to the nearest tenth and the answer is: 4.9

3 0

3 years ago

Read 2 more answers

Answer please Its for a timed test please answer

ruslelena [56]

Answer:

Step-by-step explanation:

the absolute value of -5 = 5.

5+8=13.

Hope this helped.

3 0

2 years ago

Read 2 more answers

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

3 years ago

Find the sum and product of the roots. 3x^ 2 - 4x - 7 = 0

victus00 [196]

Given the quadratic function, to get the roots we factorize:
3x²-4x-7=0

3x²+3x-7x-7=0
3x(x+1)-7(x+1)=0
(3x-7)(x+1)=0
thus the roots are
x=-1 or x=3/7
thus the sum of the roots will be:
-1+3/7
=-4/7

6 0

3 years ago