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katrin [286]
3 years ago
10

Find the zeros of the function.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(x - 2)(3x + 3) = 0

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

3x + 3 = 0 ( subtract 3 from both sides )

3x = - 3 ( divide both sides by 3 )

x = - 1

Hence

smaller x = - 1

larger x = 2

docker41 [41]3 years ago
5 0

Step-by-step explanation:

• <em><u>To</u></em><em><u> </u></em><em><u>find</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>Zero</u></em><em><u>s</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>funct</u></em><em><u>ion</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>equate</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>function</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>here</u></em><em><u> </u></em><em><u>g</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>zero</u></em><em><u> </u></em>

<em>=</em><em>></em><em> </em><em><u>g</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>)</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>)</u></em>

<em>g</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em>(</em><em> </em><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>either</em><em> </em><em>,</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>OR</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>OR</em><em> </em><em>3</em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>)</em>

<em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>OR</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em>

<em>•</em><em> </em><em>Smaller</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em>

<em>•</em><em> </em><em>Larger</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em>

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Step-by-step explanation:

3 + 3(k + 3) = 6(k - 2) + 9

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You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.
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Answer:

a. How many bowls could you glaze?

6 bowls

How many plates could you glaze?

10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

How many plates can you glaze?

2 plates

How much glaze will be left over?

8/9 of glaze would be left

c. How many of each object could you glaze so that there is no glaze left over? Explain how you found your answer.

4 4/23 bowls and 4 4/23 plates

Step-by-step explanation:

We are told in the question

Number of pints of glaze = 6 pints

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

a.

How many bowls could you glaze?

7/8 pint = 1 bowl

6 pints = x

Cross Multiply

x = 6 pints/ 7/8

= 6 × 8/7

= 48/7

= 6.8571428571 bowls

We can only glaze whole numbers of a bowl, hence, we can only glaze 6 bowls

How many plates could you glaze?

9/16 pint = 1 bowl

6 pints = y

y = 6 pints/ 9/16

= 6 × 16/9

= 10.666666667 plates

We can only glaze whole number of a plate, hence, we can only glaze 10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

1 bowl = 7/8 pints

5 bowls = z

Cross Multiply

z = 5 × 7/8pints

= 4 3/8 pints of glaze would be used for bowls

How many plates can you glaze?

The rest is for plates, hence:

The amount of glaze left for plates is calculated as:

6 pints - 4 3/8

1 5/8 pints of glaze would be left over to glaze plates.

So therefore,

9/16 pints = 1 plate

1 5/8 pints =

= 2 8/9

Hence we can only glaze 2 plates

How much glaze will be left over?

2 8/9 pints - 2 pints

= 8/9 pints of glaze.

c. How many of each object could you glaze so that there is no glaze left over?

We have 6 pints of glaze

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

Let the number of each objects be represented by x

7/8 × x + 9/16 × x = 6 pints

= 4 4/23 bowls and 4 4/23 plates

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Step 1: Find the GCF. List out the factors of the numerator and the denominator. 1, 3, 9 are the factors of 9, while 1, 2, 3, 4, 6, 9, 12, 18, and 36 are the factors of 36. 9 is a common factor of both of them, so the GCF is 9.

Step 2: Divide the numerator and denominator by 9 (the GCF). 9/9 is 1. 36/9 is 4. This means that our fraction is 1/4. The fraction is in simplest form.

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