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vodka [1.7K]
3 years ago
14

a bowl of candies contains the following makeup of colors: 4 red, 2 yellow, 5 green, and 1 purple. taina is selecting a candy at

random from this bowl. she does not like the color red. what is the probability that taina does NOT select a red candy
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

<u>Candies</u>

4 red

2 yellow

5 green

1 purple

- Taina doesn't like red candies.

4/4+2+5+1 = 4/12

4/12 is the probability Taina <em>will</em> get a red candy, but we're looking for the opposite.

12/12 - 4/12 = 8/12 = 2/3

The probability Taina will not select a red candy is 2/3.

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The measurement around the circle

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Which quadrant of the coordinate plane has ordered pairs in the form of a positive number
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Quadrant IV

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8 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
Help please this is due Friday
alexdok [17]
X=0.697
x=4.30
Hope this helps
7 0
3 years ago
Help with the CORRECT answer pretty please
lilavasa [31]
The answer would be (3,-1)
7 0
3 years ago
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