Question

My calculator wasn’t working for this I’m not sure how to solve it but help would be coolio

Answer 1

We know that:

$_nP_k = \dfrac{n!}{(n-k)!}$

so in this case $n = 5$, $k=3$ and:

$_5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5!}{2!}=\dfrac{5\cdot4\cdot3\cdot2\cdot1}{2\cdot1}=\dfrac{120}{2}=\boxed{60}$