Answer:- 3.68M.
Solution:- We have a 22.0% by mass solution of ethylene glycol and it's density is 1.04 gram per mL. It ask to calculate the molarity of the solution. We know that molarity is moles of solute per liter of solution. So, we need to figure out the moles of ethylene glycol and volume of solution.
Let's say we have 100 grams of the solution. Then mass of ethylene glycol would be 22.0 grams. Molar mass of ethylene glycol is 62.07 gram per mol.
Let's calculate it's moles first:

= 
From mass and density we calculate the volume of the solution and convert it to liters as:

= 0.0962 L

= 3.68M
So, the molarity of ethylene glycol solution is 3.68M.
Well, if the coefficients are both 1, then you will make 8.21 moles.
See the equation is:
x moles= (8.21mol FeS₂)×(1 mole H₂SO₄ ÷ 1 mole FeS₂) = 8.21 moles H₂SO₄
So if you change the coefficients of the equation, your product will be a different number.
Example:
x moles= (8.21mol FeS₂)×(2 mole H₂SO₄ ÷ 1 mole FeS₂) = 16.4 moles H₂SO₄
I hope this helps you out!
Brady
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