Answer:
1 mol SO2 contains 6.0213*10^23 molecules
6.023*10^24 molecules = 10 mol SO2
Equation
S(s) + O2(g) → SO2(g)
1 mol S reacts with 1 mol O2 to prepare 1 mol SO2
To prepare 10 mol SO2 you require : 10 mol S plus 10 mol O2
And that is the answer to the question
If you want a mass :
Molar mass S = 32 g/mol You require 10 mol = 320 g
Molar mass O2 = 32 g/mol :You require 10 mol = 320 g
If they're different sizes and densities, you are able to separate the substances.
Sodium tritioantimonate(III) and water are the products of the reaction between antimony(III) oxide and sodium hydroxide.
Sb2O3(s)+NaOH(aq)→Na3SbO3(aq)+H2O(l)
Balance the reaction from antimony, sodium, then hydrogen and oxygen.
Sb2O3(s)+6NaOH(aq)→2Na3SbO3(aq)+3H2O(l)
The equation is already balanced.
When each element in a chemical reaction has the same number of atoms and total charge on both the reactants and product sides of the equation, the reaction is said to be balanced. In other words, both sides of the reaction have an equal mass and charge of the components.
Because a chemical reaction is simply an arrangement of the atoms of the supplied elements, a chemical equation must be balanced. For the law of conservation of mass to be followed, the chemical equation must be balanced.
Learn more about chemical reaction here:
brainly.com/question/3461108
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Answer:
5118.50 J
Explanation:
pΔv=nRΔT ;
therefore, ΔT=PV/nR
ΔT = (6.4×10^5)(3.2×10^(-3)/1×8.314
ΔT= 2.4633×10^2 = 246.33 K
specific heat at constant pressure is given as:
c_p = 3/2R
c_p = 12.5 J/mol K
Now, substitute in equation (1)
we know that
Q=ΔU+W ;
and
W=pΔV= 6.4×10^5×3.2×10^(-3) = 2048 J
now
ΔU=CvΔT = 12.465×246.33 =3070.50 J ;
therefore
Q=3070.50+2048= 5118.50 J
What following?? Conditions??
