All categories

3 years ago

In Indian cuisine, sometimes a papaya is added to make meat cook faster. Explain how this method works.

1 answer:

8 0

In Indian cuisine, sometimes a papaya is added to make meat cook faster. This is possible since papaya contains enzymes that functions as a meat tenderizer which is called the papain. Adding the papaya while cooking will excrete out the enzyme and do its function which is to tenderize the meat.

You might be interested in

What is the reaction corresponding to the standard enthalpy of formation of K2SO3(s)?

nalin [4]

Answer:

2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s)

Explanation:

The standard enthalpy of formation of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.

Thus, to calculate the standard state of formation of a compound you must:

1. Identify the elements that form the compound
2. Identify the standard form of each element
3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.

Applying that to our compound K₂SO₃

1. Elements:

potassium, K;
sulfur, S; and
oxygen, O.

2. Standard forms of the elements:

potassium: solid, K(s)
sulfur: solid, octatomic molecules, S₈ (s)
oxygen: diatomic gas, O₂(g)

3. Reaction:

K(s) + S₈ (s) + O₂(g) → K₂SO₃ (s)

Balance, keeping one mole of K₂SO₃. You will need to use fractional coefficients for some elements:

2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s) ← answer

8 0

3 years ago

Questions

Ulleksa [173]

Answers:

See below

Step-by-step explanation:

1. Most food energy

(a) Pringles

Heat from Pringles + heat absorbed by water = 0

m₁ΔH + m₂CΔT = 0

1.984ΔH + 100 × 4.184 × 18 = 0

1.984ΔH + 7530 = 0

ΔH = -7530/1.984 = -3800 J/g

(b) Cheetos

0.884ΔH + 418.4 × 13 = 0

ΔH = -5400/0.884 = -6200 J/g

Cheetos give you more food energy per gram.

(c) Snickers

Food energy = 215 Cal/28 g × 4184 J/1 Cal = 32 000 J/g

The food energy from Cheetos is much less than that from a Snickers bar

2. Experimental uncertainty

The experimental values are almost certainly too low.

Your burning food is heating up the air around it, so much of the heat of combustion is lost to the atmosphere.

3. Percent efficiency

Experimental food energy = 3800 J/g

Actual food energy = 150 Cal/28 g × 4184 J/1 Cal = 22 000 J/g

% Efficiency = Experimental value/Actual value × 100 %

= 3800/22 000 × 100 %

= 17 %

6 0

3 years ago

The enthalpy of fusion of H2O (s) at its normal melting point is 6.01 kJ/mol. What is the entropy change for freezing 1 mole of

Rom4ik [11]

Answer:

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

Number of moles = 1

Entropy change (S) = ?

The formular relationship between entropy and enthalpy is given as;

ΔS=ΔH/T

Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

ΔS = 6.01/273

ΔS = 0.0220kJ/Kmol

ΔS = 0.02201 * 1000 = 22.01J/Kmol

3 0

3 years ago

Every Methane molecule looks different. True or false?

Akimi4 [234]

Answer:

False

Explanation:

Molecules of the same substance are made up of the same type of atoms and look exactly alike.

Hence, if I have two molecules of methane having exactly the same atoms of carbon and hydrogen,the both are indistinguishable from each other based on appearance.

Hence all molecules of methane are exactly alike if they are composed of atoms of the same isotope of hydrogen and carbon.

8 0

4 years ago

1. How many sublevels are in the following principal energy levels?

mafiozo [28]

Explanation:

a 1 ( only "s"

b 2 ( "s" ,"p" )

c 3 ( "s" , "p" , "d")

d 4 ( "s", "p" , "d", "f")

e 5 ( "s", "p", "d", "f", "g")

f 6 ( "s", "p", "d", "f", "g", "h" )

6 0

4 years ago