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Artist 52 [7]
3 years ago
11

Complete each blank to find an expression that is equal to 16%.

Mathematics
2 answers:
Luda [366]3 years ago
6 0

Answer:

a. __ for every 100.

16 per cent is 16/100 or 16 per hundred, so the answer will be 16 here.

b. __for every 50.

Now, 50 is half of 100, so half of 16 will be 8.

c. 1 for every __.

\frac{8/8}{50/8}

\frac{1}{6.25} = Means 1 out of 6.25

d. 0.5 for every __.

We will half the part C answer.

It will be = 6.25/2=3.125

almond37 [142]3 years ago
5 0
A. 16 for every 100
b. 8 for every 50
c. 1 for every 16
d. 0.5 for every 8
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Using numbers, variables and symbols, write an expression that describes the following The product of 5 and n, minus the quotien
slavikrds [6]

Answer:

5n-t/7

Step-by-step explanation:

The product of 5 and n puts them in the same category and product means times and your going to minus t divided by 7

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Which statements is an example of the symmetric property of congruence?
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Answer:

I believe the answer is C.

Step-by-step explanation:

Example:

For any angles A and B , if ∠ A ≅ ∠ B , then ∠ B ≅ ∠ A . Order of congruence does not matter.

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The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
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Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

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Describe the error in the work below.
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If u take you answer as x and do the problem u will see that they are equal so u would have to have a different answers for x or say -6.1 is greater than or equal to -17.4 + 11.3
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A common factor for all of them is 8
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