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tiny-mole [99]
3 years ago
9

11 22 33 44 55 66 77 what comes next

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0
The number that comes next is 88
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Which is the first question in brainly
Vedmedyk [2.9K]

Answer:

this question

Step-by-step explanation:

3 0
3 years ago
What is the solution to this system of equations?
vovangra [49]

3x + 2y=-10 equation 1

y=-x -4 equation 2

use the substitution method of elimination to get the answer to the question.

*using substitution

substitute equation 2 in one and we get

3x +2(-x-4)=-10

3x- 2x-8=-10

x=-2 and y=-2

Answer:

B

7 0
2 years ago
Read 2 more answers
What are the zeros of the quadratic function? f(x)=3x2−300 Enter your answers in the boxes.
nata0808 [166]
Hi there!

We can find the zeros of a function by solving f(x) = 0. We find the following:

3 {x}^{2} - 300 = 0
Add 300 to both sides.

3 {x}^{2} = 300
Divide by 3.

{x}^{2} = 100
Take the root and minus root of both sides.

x = \sqrt{100} = 10 \\ or \\ x = - \sqrt{100} = - 10

Therefore, the zeros are
x = 10 and x = -10.

~ Hope this helps you!
5 0
4 years ago
What does the equation y=2x + 3 represent relationship.
xxTIMURxx [149]

Answer:

Linear Proportional Relationship

General Formulas and Concepts:

<u>Algebra I</u>

  • Linear - Any degree of 1 in the form of y = mx + b or Ax + By = C
  • Nonlinear - Any degree higher than 1

Step-by-step explanation:

<u>Step 1: Define</u>

y = 2x + 3

<u>Step 2: Identify</u>

We see we have a linear equation in y = mx + b. We can also see that it is a degree of 1. Therefore, it is a Linear proportional relationship.

6 0
3 years ago
How would the expression x2 +8 be rewritten using Sum of Cubes?
Nadusha1986 [10]

Answer:

x^3+8=(x+2)(x^2-2x+4)

So if they meant x^3+8 then the answer is:

(x+2)(x^2-2x+4).

The choice this corresponds to is A.

Step-by-step explanation:

The sum of cubes formula for factoring or expanding:

a^3+b^3=(a+b)(a^2-ab+b^2)

You have I'm assuming they meant:

x^3+8.

Compare x^3+8 to a^3+b^3.

You should see in place of a you have x.

You should also see in place of b you have 2.

a^3+b^3=(a+b)(a^2-ab+b^2)

x^3+8

x^3+2^3

x^3+2^3=(x+2)(x^2-2x+2^2)

x^3+8=(x+2)(x^2-2x+4)

Let's check it for fun.

So we are going to use the distributive property.

We are going to distribute all the terms in the first ( ) to all the terms in the second ( ).

x(x^2-2x+4)   +   2(x^2-2x+4)

x^3-2x^2+4x   + 2x^2-4x+8

Combine like terms:

x^3-2x^2+2x^2+4x-4x+8

Simplify the grouping of like terms:

x^3+0x^2+0x+8

0 times anything is 0:

x^3+8

8 0
4 years ago
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