Answer:
I will first divide the figure into two which gives me a rectangle and a semi circle
area of figure = area of rectangle + area of semi circle
= [(length × width)+(1/2πr²)]
[(10×15)+(1/2×22/7×5×5)]
[(150)+(39.29)]
= 189.3cm²
Answer:
37
Step-by-step explanation:
<BRD & <FRK are vertical angles
The answer is 64. Length times width times height.
y < x; y > 5; x > 2
A. (9; 7) → x = 9; y = 7
y < x → 7 < 9 TRUE
y > 5 → 7 > 5 TRUE
x > 2 → 9 > 2 TRUE
B. (7; 5) → x = 7; y = 5
y > 5 → 5 > 5 FALSE
C. (-3; 8) → x = -3; y = 8
y < x → 8 < -3 FALSE
D. (3; 2) → x = 3; y = 2
y > 5 → 2 > 5 FALSE
E. (8; 6) → x = 8; y = 6
y < x → 6 < 8 TRUE
y > 5 → 6 > 5 TRUE
x > 2 → 8 > 2 TRUE
F. (6; 6) → x = 6; y= 6
y < x → 6 < 6 FALSE
Answer: A. (9; 7) and E. (8; 6)
9514 1404 393
Answer:
∠MLP = 28°
Step-by-step explanation:
The sum of angles in the quadrilateral is 360°. LN bisects angle L, so we have ...
2(∠MLP) +108° +88° +108° = 360°
2(∠MLP) = 56°
∠MLP = 28°