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NikAS [45]
3 years ago
8

Solve the compound inequality:2x-8≥4 or 8x+7<15

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0
An inequality<span> is a sentence with <, >, ≤, or ≥ as its verb. An example is 3x - 5 < 6 - 2x. To </span>solve<span> an inequality is to find all values of the variable that make the inequality true. Each of these numbers is a solution of the inequality, and the set of all such solutions is its </span>solution set<span>. Inequalities that have the same solution set are called equivalent inequalities.</span>
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What is the equation of the quadratic graph with a focus of (-4,17/8) and a directrix of y=15/8
Temka [501]
So hmm notice the graph below

based on where the focus point is at, and the directrix, then, the parabola is opening upwards, meaning the squared variable is the "x"

\bf \begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}

now, keep in mind, the vertex is at coordinates h,k
the vertex itself is half-way between the focus and directrix
the directrix is at y=15/8 and the focus is at y=17/8
so, half-way will then be \bf \cfrac{17}{8}-\cfrac{15}{8}=\cfrac{2}{8}\iff \cfrac{1}{4}

well, so is 1/4 between the focus point and the directrix, half of that is 1/8
so, if you move from the focus point 1/8 down, you'll get the y-coordinate for the vertex, or 1/8 up from the directrix, since the vertex is equidistant to either

what's the "p" distance? well, we just found it, is just 1/8

so, the x-coordinate is obviously -4, get the y-coordinate by 17/8 - 1/8   or 15/8 + 1/8

and plug your values (x-h)² = 4p(y-k)   and then solve for "y", that's the equation of the quadratic

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3 years ago
What is the domain and range of 4n/n-5 -2?
nlexa [21]

Answer:

Domain: (-∞, 5)∪ (5, ∞)

Range: (-∞, 2)∪ (2, ∞)

7 0
3 years ago
Read 2 more answers
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