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creativ13 [48]
4 years ago
10

8 1/4x5 1/2what is the answer to this

Mathematics
2 answers:
julsineya [31]4 years ago
5 0

the answer is 45.375

Free_Kalibri [48]4 years ago
4 0

45.375 is the answer

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Kirsten tried to evaluate the expression {12 x 2 - 8} x 2. Her work is below.
Vsevolod [243]

Answer:

step 1

Step-by-step explanation:

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What is the average of 3.28+6.90+5.30+12.00+4.77
schepotkina [342]
The answer should be 32.25
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HEYYYYYYYYYYY I NEED HELPPPPPP WILL GIVE BRAINLIST
tino4ka555 [31]

Answer:

1/3

Step-by-step explanation:

There are six triangles

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Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Inessa ran 3 laps in 8 minutes. How long would it take her to run 10 laps at this pace? (This is proportions)
Degger [83]

Answer:

26.6 minutes

Step-by-step explanation:

Set up a proportion

3/8 = 10/x

cross multiply

3x = 80

x = 26.6

5 0
3 years ago
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