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frez [133]
4 years ago
10

The graph below shows the solution to which system of inequalities​

Mathematics
2 answers:
dem82 [27]4 years ago
6 0

Answer: b

Step-by-step explanation:

dexar [7]4 years ago
3 0

Answer:

Option A is the answer

Step-by-step explanation:

In the figure attache a solid straight line has been drawn at y = 2 and the area above this line will be represented by y ≥ 2

Similarly area below the dotted line will be y < x

Now area which is common to both is colored area in blue.

So, the system of equations will be y ≥ 2 and y < x

Option A. is the answer.

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Express the following as powers of 64: (e) 1 (f) 1/64 (g) 1/8 (h) 1/2 (I) 1/64
____ [38]

Answer:

(e) 1 =64⁰

(f) 1/64 = 64⁻¹ negative one power

(g) 1/8 = 64⁻¹/² negative one half power

(h) 1/2 = 64⁻1/6 negative one/sixth power

(I) 1/64 same as (f) ??

Step-by-step explanation:

6 0
3 years ago
Name two ways that saving and investing are different
aleksandrvk [35]
Saving and investing are different because investing will generate and duplicate the initial money put it in while savings will stay the same amount without duplicating as it would if it was invested.
6 0
3 years ago
3.
nikitadnepr [17]

i think the answer is linear I am not sure though

4 0
3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
3 years ago
In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which
mario62 [17]

2 out of 50 were tagged.

Divide 2 by 50:

2/50 = 0.4 ( This is 4% of the fish were tagged).

Now divide the number of fish caught by the percentage that were tagged:

50 / 0.04 = 1250

The number of fish in the pond is C. 1250

6 0
3 years ago
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