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Dima020 [189]
3 years ago
11

What is a measure of the amount of matter in an object? A). density B). mass C). gravity D). weight

Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
8 0
The corrent answer will be b mass :)
dybincka [34]3 years ago
8 0
I think the answer would be B. mass
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the volume of a gas with a pressure of 1.2 atmospheres increases from 1 to 4 what is the final pressure of the gas assuming cons
Oksana_A [137]

Answer:

the answer is is putting ptessure on the gas

Explanation:

7 0
3 years ago
The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when
tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)

The half-cell reactions are:

Oxidation half reaction (anode):  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction (cathode):  Pb^{2+}+2e^-\rightarrow Pb

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 25^oC=273+25=298K

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = +0.63 V

E_{cell} = cell potential for the reaction = ?

[Zn^{2+}] = 3.5 M

[Pb^{2+}] = 2.0\times 10^{-4}M

Now put all the given values in the above equation, we get:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

E_{cell}=0.50V

Therefore, the cell potential for this reaction is 0.50 V

5 0
4 years ago
How many orbitals are in Phosphorus
Viefleur [7K]

Answer:

3

three half-filled orbitals each capable of forming a single covalent Bond and an additional lone - pair of electrons

8 0
3 years ago
Read 2 more answers
What volume of a 0.0943 M H2SO4 solution, to three sig figs, is needed to neutralize 161.2 mL of a 0.0158 M LiOH solution given
ArbitrLikvidat [17]
I don't know the answer to long I just want points  so plz like and thank me jk  the answer is 12H2o
5 0
3 years ago
HELP
Jobisdone [24]

Answer:

hello,

first one is 25.15

second is 301.55

Explanation:

honestly if you look up on the internet there is a converter to get you your answers

5 0
3 years ago
Read 2 more answers
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