If I'm correct the answer should be a series circuit :) Hopefully this helps you out
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
Answer:
48g of Magnesium.
Explanation:
We know that:
Mole=given mass/molar mass
Then, moles of aluminum = 54/27 = 2.
A/c to question ,
For 2 moles of magnesium it's mass is 2×24=48g.
Hence, the required mass for same number of magnesium atoms is 48g.
(Hope this helps can I pls have brainlist (crown)☺️)
Answer: C. There is more plate movement in California.
Explanation:
Answer:
2.29 × 10²⁴ atoms Na
Explanation:
Step 1: Define
Avagadro's Number: 6.02 × 10²³ atoms, molecules, formula units, etc.
Step 2: Stoichiometry
= 2.2876 × 10²⁴ atoms Na
Step 3: Simplify
We have 3 sig figs.
2.2876 × 10²⁴ atoms Na ≈ 2.29 × 10²⁴ atoms Na
