Answer: <span>The main interactions between molecules of hydrogen chloride are examples of
Dipole-Dipole Interactions.
Explanation: The bond between Hydrogen and Chlorine is
Polar Covalent Bond as the
electronegativity difference between these two elements is
0.96 which is greater than 0.4. Chlorine being more electronegative attracts the electrons from Hydrogen making the Hydrogen
partial positive and itself
partial negative. The two poles on HCl makes it a dipole. Now, one HCl (a dipole) interacts with another HCl (another Dipole) through their opposite charges and creates
Dipole-Dipole Interaction. The picture is as below, the
green dashed lines are interactions,
</span>
Answer:
ΔH = 1270kJ
Explanation:
Let's consider the following thermochemical equation.
B(s) + 3/2 O₂(g) → B₂O₃(s), ΔH = −1270kJ
Since ΔH < 0, this reaction is exothermic. According to the Lavoisier-Laplace law, if we reverse a reaction, its enthalpy will have the same value and opposite sign than the direct reaction.
B₂O₃(s) → B(s) + 3/2 O₂(g), ΔH = 1270kJ
For the inverse reaction, ΔH > 0, which means that it is endothermic.
The answer is false i just did that question
Answer:
pH of resulting solution = 7.98
Explanation:
The balanced equation
HA + NaOH - Na+ + A- + H2O
Number of moles of A = Number of moles of HA = Number of moles of NaOH
= 35.8/1000 * 0.020 = 0.000716 mol
Initial concentration of A = 0.000716/0.0608 = 0.01178 M
pKb = 14 – pKa = 14 -3.9 = 10.1
Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11
Kb = [HA][OH-]/[A-]
Kb = a^2/(0.01178 -a) = 7.943 * 10^-11
a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0
a = 9.673 * 10^-7
OH- = a = 9.673 * 10^-7 M
pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02
pH = 14-6.02 = 7.98
Erica is likely to use reverse osmosis process.it is the method used in the industry to treat water in oil and gas industry .or ultra filtration method is also employed