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Dafna11 [192]
3 years ago
5

Sulfurous acid reacts with barium hydroxide.

Chemistry
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

Ba(OH)2 + H2SO3 = BaSO3 + H2O -

Explanation:

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The main interactions between molecules of hydrogen chloride are examples of
saveliy_v [14]
Answer:
            <span>The main interactions between molecules of hydrogen chloride are examples of Dipole-Dipole Interactions.

Explanation:
                   The bond between Hydrogen and Chlorine is Polar Covalent Bond as the electronegativity difference between these two elements is 0.96 which is greater than 0.4. Chlorine being more electronegative attracts the electrons from Hydrogen making the Hydrogen partial positive and itself partial negative. The two poles on HCl makes it a dipole. Now, one HCl (a dipole) interacts with another HCl (another Dipole) through their opposite charges and creates Dipole-Dipole Interaction. The picture is as below, the green dashed lines are interactions,

</span>

6 0
3 years ago
Click on the Delta H changes sign whan a process is reversed button within the activity and analyze the relationship between the
andreev551 [17]

Answer:

ΔH = 1270kJ

Explanation:

Let's consider the following thermochemical equation.

B(s) + 3/2 O₂(g) → B₂O₃(s), ΔH = −1270kJ

Since ΔH < 0, this reaction is exothermic. According to the Lavoisier-Laplace law, if we reverse a reaction, its enthalpy will have the same value and opposite sign than the direct reaction.

B₂O₃(s) → B(s) + 3/2 O₂(g), ΔH = 1270kJ

For the inverse reaction, ΔH > 0, which means that it is endothermic.

6 0
4 years ago
Plants do not adapt to their environment because they do not compete for resources.
olga_2 [115]
The answer is false i just did that question
8 0
3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
3 years ago
Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oli. What method is she most l
patriot [66]

Erica is likely to use reverse osmosis process.it is the method used in the industry to treat water in oil and gas industry .or ultra filtration method is also employed

7 0
4 years ago
Read 2 more answers
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