A. H2O is the substance reduced.
H2O + 2e^(-) →H_2 + 2OH^(-)
The substance that gains electrons is reduced.
Remember OIL <em>RIG </em>(<em>R</em>eduction <em>I</em>s <em>G</em>ain of electrons) and
LEO the lion says <em>GER</em> (<em>G</em>ain of <em>E</em>lectrons is <em>R</em>eduction).
Answer : The correct option is B.
Explanation :
The temperature of the warm water is higher than the cold water. That means as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases.
As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases (i.e, quick evaporation), thereby increasing the vapor pressure of warm water.
Hence, the correct answer is, (B) Warm water evaporates more quickly.
Answer:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, the rate is given as:
![rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}](https://tex.z-dn.net/?f=rate%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7B%5CDelta%20%5BHBr%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BBr_2%5D%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7B%5CDelta%20%5BH_2%5D%7D%7B%5CDelta%20t%7D)
It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.
Therefore, the answer is:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Best regards.
solids have particles that are closely packed to each other that they can barely move
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).
