Answer:
The answer is
<h2>3.0 g/cm³</h2>
Explanation:
To find the density of a substance when given the mass and volume we use the formula
<h3>
</h3>
From the question
mass = 15 g
volume of rock = 5 cm³
The density of the substance is
We have the final answer as
<h3>3.0 g/cm³</h3>
Hope this helps you
Answer:
When there remains one-quarter of the sample, the age of the sample is 10940 years
Explanation:
<u>Step 1:</u> Data given
The half-life of C-14 is 5470 years.
The half- life time is the time required for a quantity to reduce to half of its initial value.
This means after 5470 years there remains half of the C-14 sample.
To remain a quarter of the sample, another cycle of 5470 years is required.
This means 2 half-lives should have passed to remain a quarter of the sample.
<u>Step 2</u>: Calculate it's age
t/(t/1/2) = 2
⇒ with t = the age (or time) of the sample
⇒ with t(1/2) = the half-life time of the sample = 5470 years
⇒ with 2 = the number of halvf- lives passed
t/5470 = 2
t = 2*5470 = 10940 years
When there remains one-quarter of the sample, the age of the sample is 10940 years
Answer:
A hydrogen molecule forms from two hydrogen atoms, each with one electron in a 1 s orbital. The two hydrogen atoms are attracted to the same pair of electrons in the covalent bond. The bond is represented either as a pair of “dots” or as a solid line. Each hydrogen atom acquires a helium-like electron configuration. Shared electrons located in the space between the two nuclei are called bonding electrons. The bonded pair is the “glue” that holds the atoms together in molecular units. The hydrogen molecule is the simplest substance having a covalent bond.
Explanation:
Answer:
m O2 = 116,16 g
Explanation:
Ca(ClO3)2 ------------> CaCl2 + 3O2
n Ca(ClO3)2 = 250/207 = 1,21 mol
n O2 = 3n Ca(ClO3)2 = 1,21 * 3 = 3,63 mol
m O2 = 3,63 * 32 = 116,16 g
