Answer:
solid change directly into a vapor in the process known simply as freezing
Answer:
There was an improvement in accuracy. There was no change in precision.
Explanation:
<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).
The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.
Answer:
Option a. 0.5 m/s
Explanation:
This graph shows a straight line, where "Y" axis would be "Position" and "X" graph would be "Time". The ecuation that would describe this straight line is Y= aX + 1 , where "a" is the slope or inclination for this graph, and would give us the speed of the object
How do we find the slope (and hence, the speed)?: if you notice this graph, you will check that:
-When X (Time) is zero, Y (Position) is 1
-When X (Time) is 2, Y (Position) is 2
With these 4 points, you can calculate the slope (which will call "m") for this graph with:
m = (Y2-Y1)/(X2-X1) so: Y2=2, Y1=1, X2=2, X1=0
Which gives us: m=1/2 (0.5), the slope or speed of the object: 0.5 m/s
