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3 years ago

12

Jessie sorted the coins in her bank. She made 7 stackes of 6 dimes and 8 sacks of 5 nickels. She then found 1 dime and 1 nickle.

How many nickles and dimes does jessie have now.

1 answer:

Bess [88]3 years ago

8 0

Answer:

43 dimes = $4.30 41 nickels =$1.96. hope this helps

Step-by-step explanation:

6x7= 42

42+2=43

43x10=430

8x5=40

40+1=41

41x5=196

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which of the following are the dimensins of a rectangle that has a perimeter of 148 and an area of 144

atroni [7]

The dimensions are 72x2
Because $72*2=144$ & $72+72+2+2=148$
Your'e Welcome!!
Hopefully this is Brainliest worthy!!

8 0

3 years ago

Use a truth table to verify the ﬁrst De Morgan law (p ∧ q)’ ≡ p’ ∨ q’.

Nutka1998 [239]

Answer:

(p ∧ q)’ ≡ p’ ∨ q’

Step-by-step explanation:

First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.

p ∧ q

t t t

t f f

f f t

f f f

next step is getting the opposite

(p∧q)'

<em>f</em>

<em> t</em>

<em> t</em>

<em> t</em>

Then we get p' V q', V is true (t) when the first or the second is true.

p' V q'

f <em>f</em> f

f <em>t</em> t

t <em>t</em> f

t <em>t</em> t

Let's compare them, ≡ is true if the first is equal to the second one.

(p∧q)' ≡ (p' V q')

<em>f f </em>

<em> t t</em>

<em> t t</em>

<em> t t</em>

Both are true, so

(p ∧ q)’ ≡ p’ ∨ q’

6 0

3 years ago

Write one sine and one cosine equation for each graph below.

pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0

3 years ago

6×5/6=24 I think I hope

Rom4ik [11]

No 6x5/6 is 5.
6x5 is 30.
30/6=5
Ignore @popmypussy
Hope i could help!
Thunderclan89

7 0

3 years ago

Find each Of change. Round to the nearest whole percent if necessary. State whether the percent Of change is an increase or 1. O

Alenkasestr [34]

Answer:

1. The percentage change is 74% and it is a percentage decrease

2. The percentage change is 15% and it is a percentage decrease

3. The percentage change is 20% and it is a percentage decrease

4. The percentage change is 43% and it is a percentage increase

5. The percentage change is 40% and it is a percentage decrease

6. The percentage change is 39% and it is a percentage decrease

Step-by-step explanation:

Given

$1.\ Original = 5; New = 1.3$

$2.\ Original = 160; New = 136$

$3.\ Original = 15; New = 12$

$4.\ Original = 7; New = 10$

$5.\ Original = $30; New = $18$

$6.\ Original = 9.6; New = 5.9$

Required

Determine the percentage change and state whether it's an increase or decrease

Percentage change is calculated as:

$\%Change = \frac{New - Original}{Original} * 100\%$

$1.\ Original = 5; New = 1.3$

$\%Change = \frac{1.3 - 5}{1.3} * 100\%$

$\%Change = \frac{-3.7}5} * 100\%$

$\%Change = \frac{-3.7 * 100\%}{5}$

$\%Change = \frac{-370\%}{5}$

$\%Change = -74\%$

<em>The percentage change is 74% and it is a percentage decrease</em>

$2.\ Original = 160; New = 136$

$\%Change = \frac{136 - 160}{160} * 100\%$

$\%Change = \frac{-24}{160} * 100\%$

$\%Change = \frac{-24 * 100\%}{160}$

$\%Change = \frac{-2400\%}{160}$

$\%Change = -15\%$

<em>The percentage change is 15% and it is a percentage decrease</em>

$3.\ Original = 15; New = 12$

$\%Change = \frac{12- 15}{15} * 100\%$

$\%Change = \frac{-3}{15} * 100\%$

$\%Change = \frac{-3* 100\%}{15}$

$\%Change = \frac{-300\%}{15}$

$\%Change = -20\%$

<em>The percentage change is 20% and it is a percentage decrease</em>

$4.\ Original = 7; New = 10$

$\%Change = \frac{10- 7}{7} * 100\%$

$\%Change = \frac{3}{7} * 100\%$

$\%Change = \frac{3* 100\%}{7}$

$\%Change = \frac{300\%}{7}$

$\%Change = 43\%$ -- (approximated)

<em>The percentage change is 43% and it is a percentage increase</em>

<em></em>

$5.\ Original = $30; New = $18$

$\%Change = \frac{18- 30}{30} * 100\%$

$\%Change = \frac{-12}{30} * 100\%$

$\%Change = \frac{-12* 100\%}{30}$

$\%Change = \frac{-1200\%}{30}$

$\%Change = -40\%}$

<em>The percentage change is 40% and it is a percentage decrease</em>

$6.\ Original = 9.6; New = 5.9$

$\%Change = \frac{5.9- 9.6}{9.6} * 100\%$

$\%Change = \frac{-3.7}{9.6} * 100\%$

$\%Change = \frac{-3.7* 100\%}{9.6}$

$\%Change = \frac{-370\%}{9.6}$

$\%Change = -39\%$ -- (approximated)

<em>The percentage change is 39% and it is a percentage decrease</em>

5 0

3 years ago