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Lera25 [3.4K]
3 years ago
13

At a carnival, for every 19 games there are 10 rides. What is the ratio of games to rides?

Mathematics
2 answers:
pogonyaev3 years ago
5 0
For every 19 games there willbe 10 rides
19:10
baherus [9]3 years ago
3 0

Answer:

19:10- 1.9:1

Step-by-step explanation:

Remember that to calculate ratio you can do it just by putting together both values and see if the can be smaller, since this cannot be reduced any further, that would be your ratio 19:10 meaning that for every 19 games there are 10 rides, if you´d need a unit rate, then that would be 1.9:1 because remember that unit rates always use 1 as numerator.

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Mary said that the temperature outside on two differnt days had an absolute value 20. Kate said she was wrong because the temper
TiliK225 [7]

Answer:

Mary is correct we don’t know the temperature but it can be implied that one is 20 and the other is -20 because of absolute value which is the distance a number away from zero that means that you have two answers or two days in this case that both have an absolute value of 20

Step-by-step explanation:

5 0
3 years ago
Plz help ill give 17 points thx
Blizzard [7]

Answer:

1:6 = 7:42

Step-by-step explanation:

6 0
3 years ago
Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
4 years ago
Solve the inequality –8 < x – 14.
kodGreya [7K]
The answer is x=6. Hope this helped.
7 0
3 years ago
The scores on an achievement test are normaly distributed with mean µ = 100 and standard deviation σ = 100. What should the scor
ser-zykov [4K]

Answer:

the student should score atleast 229 to be among the top 10%.

Step-by-step explanation:

in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

P(0.4) = \dfrac{x - \mu}{\sigma}

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.

we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)

looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)

P(0.4015) = \dfrac{x - 100}{100}

1.29 = \dfrac{x - 100}{100}

x = 1.29(100) + 100

x = 229

the student should score atleast 229 to be among the top 10%.

7 0
3 years ago
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