If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer: b
Step-by-step explanation:
Answer:
g(f(0)) = 2
Step-by-step explanation:
To find g(f(0)), you must first find f(0).
f(x) = 3x + 1
f(0) = 3(0) + 1 = 0 + 1 = 1
Now you input 1 into function g(x).
g(x) = (4x + 2)/3
g(1) = [4(1) + 2]/3
g(1) = [4 + 2]/3
g(1) = 6/3
g(1) = 2
g(f(0)) = 2
Your answer will be 150 percent
Y+1 = -2x+2 (distribute)
Y=-2x + 1 (isolate y)