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leva [86]
3 years ago
10

What is the slope for this problem?

Mathematics
2 answers:
vekshin13 years ago
6 0
Slope would be 0 since the graph does not go rise or fall, it stays straight
jeka943 years ago
5 0
Anyways find );):); and chief
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Small side farms sells delicious and empire apples. One August they sold 162 more empire than delicious apples. The total number
UkoKoshka [18]

Answer:

i think it's C

Step-by-step explanation:

number of empires --- w

number of delicious' --- d

e = d + 162

e + d = 424

(d+162) + d = 424

4 0
3 years ago
Help me solve these questions <br> ?
valentinak56 [21]

Answer:

All of these?

8 0
2 years ago
Alexis bought a pyramid-like paperweight for her teacher. The paperweight has a volume of 200 cm3 and a density of 1.5 grams per
Nikolay [14]

Answer:

The density is equal to the weight divided by the volume:

\rho=\dfrac{W}{V}

The paperweight weights 300 grams.

Step-by-step explanation:

The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.

The density is equal to the weight divided by the volume:

\rho=\dfrac{W}{V}

We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.

We can use the formula of the density to calculate the weight:

\rho=\dfrac{W}{V}\\\\\\W=\rho\cdot V=1.5\;\dfrac{g}{cm^3}\,\cdot\;200\; cm^3\\\\\\W=300\;g

The paperweight weights 300 grams.

7 0
2 years ago
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
Identify the solution set of the given inequality using the given replacement set.
scoundrel [369]
Another user previously answered this same question and had a good rating, his answer was as follows:

"{-9; -6.5; -5.2}" 

Which I suppose would be answer D.
- Hope it helps.

3 0
3 years ago
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