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3 years ago

What is the slope for this problem?

Mathematics

2 answers:

vekshin13 years ago

6 0

Slope would be 0 since the graph does not go rise or fall, it stays straight

jeka943 years ago

5 0

Anyways find );):); and chief

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Small side farms sells delicious and empire apples. One August they sold 162 more empire than delicious apples. The total number

UkoKoshka [18]

Answer:

i think it's C

Step-by-step explanation:

number of empires --- w

number of delicious' --- d

e = d + 162

e + d = 424

(d+162) + d = 424

4 0

3 years ago

Help me solve these questions <br> ?

valentinak56 [21]

Answer:

All of these?

8 0

2 years ago

Alexis bought a pyramid-like paperweight for her teacher. The paperweight has a volume of 200 cm3 and a density of 1.5 grams per

Nikolay [14]

Answer:

The density is equal to the weight divided by the volume:

$\rho=\dfrac{W}{V}$

The paperweight weights 300 grams.

Step-by-step explanation:

The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.

The density is equal to the weight divided by the volume:

$\rho=\dfrac{W}{V}$

We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.

We can use the formula of the density to calculate the weight:

$\rho=\dfrac{W}{V}\\\\\\W=\rho\cdot V=1.5\;\dfrac{g}{cm^3}\,\cdot\;200\; cm^3\\\\\\W=300\;g$

The paperweight weights 300 grams.

7 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

Identify the solution set of the given inequality using the given replacement set.

scoundrel [369]

Another user previously answered this same question and had a good rating, his answer was as follows:

"{-9; -6.5; -5.2}"

Which I suppose would be answer D.
- Hope it helps.

3 0

3 years ago