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3 years ago

What is the slope for this problem?

Mathematics

2 answers:

vekshin13 years ago

6 0

Slope would be 0 since the graph does not go rise or fall, it stays straight

jeka943 years ago

5 0

Anyways find );):); and chief

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The first two terms of an arithmetic sequence are 7 and 4. Find the 7th term.

kobusy [5.1K]

EXPLANATION

If the first two terms of an arithmetic sequence are 7 and 4, then we know that an arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+(n+1)d$

Check wheter the difference is constant:

Compute the differences of all the adjacent terms:

$d=a_{n+1}-a_n$

Replacing terms:

4-7 = -3

The difference between all of the adjacent terms is the same and equal to

d = -3

The first element of the sequence is

$a_1=7$ $a_n=a_1+(n+1)d$

Therefore, the nth term is computed by

d= -3

$a_n=7+\text{ (n-1)}\cdot(-3)$

Refine

d= -3 ,

$a_n=-3n+10$

Now, replacing n=7

$a_7=-3\cdot7+10\text{ = -11}$

So, the answer is -11.

8 0

1 year ago

aimi is making a valentines day cards for everyone in her class. she plans to use a whole sheet of paper for each of her 6 close

Luba_88 [7]

You have to subtract the 6 first and then divide the rest by 1/8.
34-6=28
28×1/8=224

6 0

3 years ago

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

mario62 [17]

For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$

5 0

3 years ago

The equation of the line with slope = 3, going through point (2, 4) is:

Marina86 [1]

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\hspace{10em} \stackrel{slope}{m} ~=~ -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-3}(x-\stackrel{x_1}{2}) \\\\\\ y-4=-3x+6\implies y=-3x+10$

7 0

1 year ago

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You are completing a metric conversion in which you move the decimal 2 places to the right. This is the same as __________.

kupik [55]

Answer:

Step-by-step explanation:

8 0

3 years ago

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