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3 years ago

Answer both questions don't mind the work on the side

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

5 and 3 both have 15 in common

stealth61 [152]3 years ago

4 0

6/15 and 5/15 and that is your answer

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n order to build a scale model of the trail, the drawing is enlarged as parallelogram ABCD on the coordinate plane. If two corne

Kay [80]

I think that is the answer d

4 0

3 years ago

Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

statuscvo [17]

Answer:x=15/52

Step-by-step explanation:

Divided both side by 52

52x/52=15/52

Therefore x=15/52

7 0

3 years ago

Which equation has no solution? *

Reika [66]

Answer:

-2(x+1)=3x-2-5x

Step-by-step explanation:

It has an answer of infinite numbers

7 0

3 years ago

Read 2 more answers

Nelly owns farm land that has an area of 4.2 × 102 acres. Each year, the farm produces 6.72 × 104 bushels of corn. What is the a

juin [17]

The average amount of corn produced per acre represented in scientific notation can be found using the below formula:

$The \;average\; amount\; of\; corn\; per\; acre=\frac{Bushels \; of\; corn\; produced\; in\; farm}{Area\; of\; farm\; in\; acres}$

We are given:

$Area \; of\; FARM\; land= 4.2 \times 10^2 \; acres\\ \\ Amount \; of\; corn\; produced=6.72\; \times \; 10^4 \; bushels$

Substituting the above information in the formula, we get...

$The \; Average\; amount\; of\; corn=\frac{6.72 \times 10^4}{4.2 \times 10^2} \\ \\ \frac{6.72}{4.2} \times \frac{10^4}{10^2}\; =\; 1.6 \times 10^{4-2}\; =\; 1.6 \times 10^2\\ \\$

Conclusion:

$The \; Average \; amount\; of \; corn \; is\; 1.6 \times 10^2 \; Bushes\; per\; corn$

The average amount of corn produced per acre represented in scientific notation is option B) $1.6 \times 10^2$ bushels per acre

5 0

3 years ago

Read 2 more answers

Help please? 39 points

victus00 [196]

You cannot assume the angles add to 90, but you know since BD is an angle bisector that ABD is equal to DBC, or x-5=2x-6

x=1. this is the correct solution to the equation but gives negative angles when plugged in which isn't possible. there must be something wrong work the question

6 0

3 years ago