1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
german
3 years ago
11

Nelly owns farm land that has an area of 4.2 × 102 acres. Each year, the farm produces 6.72 × 104 bushels of corn. What is the a

verage amount of corn produced per acre represented in scientific notation?
A) 2.82 × 107 bushels per acre
B) 1.6 × 102 bushels per acre
C) 1.6 × 103 bushels per acre
D) 2.82 × 106 bushels per acre
E) 1.6 × 101 bushels per acre
Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0

Le answer is B 1.6 × 102 bushels per acre

juin [17]3 years ago
5 0

The average amount of corn produced per acre represented in scientific notation can be found using the below formula:

The \;average\; amount\; of\; corn\; per\; acre=\frac{Bushels \; of\; corn\; produced\; in\; farm}{Area\; of\; farm\; in\; acres}

We are given:

Area \; of\; FARM\; land= 4.2 \times 10^2 \; acres\\ \\ Amount \; of\; corn\; produced=6.72\;  \times \; 10^4 \; bushels

Substituting the above information in the formula, we get...

The \; Average\; amount\; of\; corn=\frac{6.72 \times 10^4}{4.2 \times 10^2} \\ \\ \frac{6.72}{4.2} \times \frac{10^4}{10^2}\; =\;   1.6 \times 10^{4-2}\; =\; 1.6 \times 10^2\\ \\

Conclusion:

The \; Average \; amount\; of \; corn \; is\; 1.6 \times 10^2 \; Bushes\; per\; corn

The average amount of corn produced per acre represented in scientific notation is option B)1.6 \times 10^2bushels per acre

You might be interested in
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio
aalyn [17]

Answer:

  StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

  (a^b)^c = a^(bc)

__

So the expression simplifies as ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}

9 0
3 years ago
Is this correct? If not can you explain why?
krok68 [10]
BOTH of your answer ARE CORRECT!
3 0
3 years ago
Help please WILL GIVE BRAINLIEST TO RIGHT ANSWER!​
Tcecarenko [31]

Answer:

I think A is the answer

but D is the correct answer "kunno"

Step-by-step explanation:

hope it helps :)

4 0
3 years ago
Read 2 more answers
The range of f(x) = 3x + 1.1 is {16.1, 19.1, 25.1). What is the domain?
givi [52]

Answer:

It’s A. (5,6,8)

4 0
3 years ago
Other questions:
  • A train traveling south leaves the station at a constant rate of 62 kilometers per hour. A second train traveling north leaves t
    6·2 answers
  • What is the answer for this??
    11·1 answer
  • A lidless box is to be made with a volume of 256256 ft cubed 3. Find the dimensions of the box that requires the least amount of
    6·1 answer
  • What is the product of 1/8 x √8?!​
    11·2 answers
  • It takes Hank 40 minutes (2/3 hours) to mow a lawn. Penny can mow the same size lawn in 30 minutes (1/2 hour). Hank and Penny fo
    11·1 answer
  • Donell compared the hours students spent each day on social networks to the hours they spent on homework. His data is shown belo
    13·2 answers
  • Hiiiiiii help me thanks!
    15·2 answers
  • I will Venmo 150$ to do my Plato classes:) maybe even 250$ need it done in 10 days I’ve already started most
    10·1 answer
  • The correlation between two scores X and Y equals 0.75. If both scores were converted to Z-scores, then the correlation between
    11·1 answer
  • In the diagram, ABCD is a parallelogram. Write an argument to support the claim that <br> M x = M y
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!