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mart [117]
4 years ago
5

All real numbers that are greater than -8 and less than 8 a.-8;

Mathematics
1 answer:
qwelly [4]4 years ago
8 0
<span>(don't know what other selections are but a is definitely Out. ) 
All real numbers that are greater than -8 and less than 8 
</span><span>-8<ℝ<8 
</span>so INTEGERs wise , it includes -7~7  , i.e. <u>-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7</u>
Real numbers wise it means you can put <u>any decimals behind the integers above</u> and it will still be included.  (ANY decimals. even <span>1.4142135 which is </span>√2) 
E.g. 7.9, 6.7, -7.8, -4.3 

_Award brainliest if helped!


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Read 2 more answers
A factory packages 4250 boxes of cereal. The number of oat cereal boxes is 715 more than the number of wheat cereal boxes. The n
ozzi
O = number of oat cereal, w = number of wheat cereal, f = number of fruit cereal:

o + w + f = 4250
o = w + 715
f = 5w

The second equation tells us the value of o in terms of w, and the third equation tells us the value of f in terms of w, so we can plug in "w + 715" for o and "5w" for f in the first equation:

o + w + f = 4250
(w + 715) + w + (5w) = 4250

Then, add like terms and subtract and divide to isolate the w:

w + 715 + w + 5w = 4250
7w + 715 = 4250                           Subtract 715 on both sides:
7w = 3535                                    Divide by 7 on each side:
w = 505

Now that we have w, we can plug it into the last equation to find f, the number of fruit cereal boxes:

f = 5w
f = 5(505)
f = 2525

Therefore, the factory packages 2525 fruit cereal boxes.
4 0
4 years ago
Find the simplified product 2 square root 5x^3(-3 square root 10x^2
Ivanshal [37]

The simplified product of 2\sqrt{5x^{3} } and -3\sqrt{10x^{2} } is -30x^{5/2} \sqrt{2}.

Given Two expressions: -3\sqrt{10x^{2} } and 2\sqrt{5x^{3} }.

We have to multiply both the expressions and it can be done as under:

-3\sqrt{10x^{2} } *2\sqrt{5x^{3} }

Firstly we have to multiply -3 with 2 to get

=-6\sqrt{10x^{2} }\sqrt{5x^{3} }

Then we have to find square root of x cube and x square which is x to the power 3/2 and x to the power 1.

=-6x^{3/2} x\sqrt{10}\sqrt{5}

Now we have to multiply both the numbers in the root to get the answer;

=-6x^{5/2} \sqrt{50}

Square root of 50 is 5 root 2.

=-6*5\sqrt{2}x^{5/2}

=-30\sqrt{2}x^{5/2}

Hence the simplified product is -30\sqrt{2}x^{5/2}.

Learn more about product here brainly.com/question/10873737

#SPJ10

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2 years ago
Can some please help me ASAP (solving rational equations)
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The answer would be A) X=5
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