All categories

3 years ago

How to multiply 8/10 and 5/6

Mathematics

2 answers:

harkovskaia [24]3 years ago

4 0

Hey there!

To multiply numbers, is basically adding them the number they are being multiplied with!

Therefore, 8x10= 80

8+8+8+8+8+8+8+8+8+8= 80

5x6= 30

5+5+5+5+5+5=30

I hope this helps!

Julli [10]3 years ago

4 0

Are u multiplying them together 8/10 divided by 5/6? 2/3 is the answer

You might be interested in

If c varies directly as (r + 1) and c = 8, when r= 3, calculate the value of r when c= 20.

Aneli [31]

Answer:

r = 9

Step-by-step explanation:

Given that c varies directly as (r + 1) then the equation relating them is

c = k(r + 1) ← k is the constant of variation

To find k use the condition c = 8 when r = 3, then

8 = k(3 + 1) = 4k ( divide both sides by 4 )

2 = k

c = 2(r + 1) ← equation of variation

When c = 20, then

20 = 2(r + 1) ← divide both sides by 2

10 = r + 1 ( subtract 1 from both sides )

9 = r

5 0

3 years ago

Read 2 more answers

A squirrel burrowed 10 holes in 8 minutes how many holes could the squirrels burrow in 12 minutes

Alenkinab [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

Please help (geometry)

jarptica [38.1K]

<h3>Answer: 54 degrees (third choice)</h3>

Explanation:

AB is a diameter of circle C. This leads to angle ACB being 180 degrees. By Thales Theorem (a special case of the inscribed angle theorem) we know that angle D is 90 degrees.

Therefore, triangle ADB is a right triangle. The acute angles (A and B) add to 90, and we can say they are complementary angles.

A+B = 90

36+B = 90

B = 90-36

B = 54 degrees

6 0

3 years ago

Use trig identities to transform the left side of the equation to the right side.

Taya2010 [7]

<u>Answer and explanation</u>

(1+sinθ)(1-sinθ)=cos²θ

We are to prove that the left hand side is equal to the right hand side.

(1+sinθ)(1-sinθ) = 1(1-sinθ) + sinθ(1-sinθ)

= 1 - sinθ + sinθ - sin²θ

= 1 - sin²θ

From the trigonometric identity sin²θ + cos²θ = 1,

1 - sin²θ = cos²θ

7 0

3 years ago

The larger of two numbers is twice the smaller increased by five. Find the two numbers if three times the larger exceeds double

melomori [17]

Answer:

Larger number is 13 and Smaller number is 4.

Step-by-step explanation:

Let the larger number be x.

Also let the smaller number be y.

We need to find the two numbers.

Given:

The larger of two numbers is twice the smaller increased by five.

framing in equation form we get;

$x=2y+5$ ⇒equation 1

Also Given:

Three times the larger exceeds double the smaller by 31

$3x=2y+31$ ⇒equation 2

Now Substituting the value of x from equation 1 in equation 2 we get;

$3(2y+5) = 2y+31$

Now Using Distributive property we get;

$6y+15 = 2y +31$

Combining the like terms we get;

$6y-2y = 31-15$

Now Using Subtraction property we get;

$4y =16$

Now Using Division property we get;

$\frac{4y}{4}=\frac{16}{4}\\\\y =4$

Now Substituting value of y in equation 1 we will find the value of x.

$x=2y+5\\\\x = 2\times4+5\\\\x=8+5\\\\x=13$

Hence Larger number is 13 and Smaller number is 4.

3 0

3 years ago