The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².
<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>
<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>
<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>
<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>
<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
Answer:
Yes, because the area of one side of the divider is approximately 24ft^2
The average of any two numbers lies between those two numbers:

Step-by-step explanation:
Just pick a bunch of values of x, and use the formula to find the corresponding value of y.
For example
When x = 0, y = 0+5 = 5 ----> Plot the point (0,5) on graph paper
When x = 1, y = 1+5 = 6 ----> Plot the point (1,6) on graph paper
When x = 2, y = 2+5 = 7 ----> Plot the point (2,7) on graph paper
Then connect the dots to get a linear graph. You should get a graph that looks like the one attached.