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seraphim [82]
4 years ago
10

There are 14 helicopters in our fleet. We'll use

Mathematics
1 answer:
vichka [17]4 years ago
4 0

Answer:

7

Step-by-step explanation:

14*(1/2)=7

i had a question like that before

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Bill has a box of markers that has a base of 8 cm by 20 cm and a height of 6 cm. Martin's pencil box has a height of 4 cm and a
Maslowich
Ok so you need to multiply the length, width, and height together for each one.
Bill: 8 x 20 x 6 = 960
Martin: 4 x 15 x 16 = 960
So Bill is right, they both have the same volume.
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3 years ago
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Simplify 5(x + 3) - 9x+4.<br>O A. 14x+7<br>O B.-4x+19<br>O C. 14x+19<br>D. -4x+7​
Julli [10]

Answer:

B

Step-by-step explanation:

distribute

5x+15-9x+4

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A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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Answer:

m=d*v

Step-by-step explanation:

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Write the expression in terms of sine only sin 9x cos 9x
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\sin 2\alpha= 2\sin \alpha\cos\alpha\quad\Rightarrow\quad\sin 9x\cos 9x=\frac{1}{2}\sin 18x
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4 years ago
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