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Marianna [84]
3 years ago
9

What is a possible equation for a function with an x-intercept of (-5,0) and a y-intercept of (0,3)?

Mathematics
1 answer:
Feliz [49]3 years ago
5 0

Answer:

The equation of a straight line is

-3 x+5 y=15

Step-by-step explanation:

Given x - intercept of (-5,0) and y- intercept is (0,3)

here (-5,0 ) point lie on x- axis and (0,3) this point lie on y- axis

we know that the x- intercept  'a' and y- intercept 'b'  formula is

\frac{x}{a} +\frac{y}{b} = 1

so given x - intercept a =-5 and y- intercept is b= 3

now the straight line equation is \frac{x}{-5} +\frac{y}{3} =1

now simplify \frac{-3 x+5 y}{15} =1

-3 x+5 y=15

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Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

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