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Marianna [84]
3 years ago
9

What is a possible equation for a function with an x-intercept of (-5,0) and a y-intercept of (0,3)?

Mathematics
1 answer:
Feliz [49]3 years ago
5 0

Answer:

The equation of a straight line is

-3 x+5 y=15

Step-by-step explanation:

Given x - intercept of (-5,0) and y- intercept is (0,3)

here (-5,0 ) point lie on x- axis and (0,3) this point lie on y- axis

we know that the x- intercept  'a' and y- intercept 'b'  formula is

\frac{x}{a} +\frac{y}{b} = 1

so given x - intercept a =-5 and y- intercept is b= 3

now the straight line equation is \frac{x}{-5} +\frac{y}{3} =1

now simplify \frac{-3 x+5 y}{15} =1

-3 x+5 y=15

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Rhombus ABCD has diagonals AC and BD which intersect at point E.

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