5/10 = /6 is 5/10 and 3/6 equivalent fraction. if so, please explain

1 answer:

8 0

$\frac{5}{10}= \frac{1\cdot5}{2\cdot5} = \frac{1}{2} \ \ \ and\ \ \ \frac{3}{6}= \frac{1\cdot3}{2\cdot3} = \frac{1}{2} \ \ \ \ \Rightarrow\ \ \ \frac{5}{10}=\frac{3}{6}$

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Answer:

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Step-by-step explanation.

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Step-by-step explanation:

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Hi :) how to do question 7 ?

Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
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now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
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we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16