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charle [14.2K]
3 years ago
10

Identify the translation rule on a coordinate plane that verifies that square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-

3,4), B'(-3,9), C'(-8,4), D'(-8,9) are congruent.
A)
(x, y) → (x - 1, y - 1)


B)
(x, y) → (x - 1, y + 1)


C)
(x, y) → (x + 1, y + 1)


D)
the squares are not congruent
Mathematics
2 answers:
noname [10]3 years ago
7 0
<h3><u>Answer:</u></h3>

The translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

<h3><u>Step-by-step explanation:</u></h3>

We are given the vertices of a square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) .

We have to find the  translation rule on a coordinate plane that verifies that square ABCD is congruent to square A'B'C'D'.

Since, the two squares o be congruent every vertex must be translated by the same rule.

So, the rule is:

(x, y) → (x + 1, y + 1)

since,

A(-4,3) → A'(-4+1,3+1)=A'(-3,4)

B(-4,8) →B'(-4+1,8+1)=(-3,9)

C(-9,3) → C'(-9+1,3+1)=(-8,4)

and D(-9,8) → D'(-9+1,8+1)=(-8,9)

Hence, the translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

skelet666 [1.2K]3 years ago
5 0
Note that each  x value increases by 1 and y values also increases by 1

C is the correct option
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