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boyakko [2]
3 years ago
7

Plz help with this problem I need to find the length of CB???

Mathematics
2 answers:
miss Akunina [59]3 years ago
5 0
tan(30)=0.57735026919 \\ 0.57735026919=  \frac{x}{20}
Multiply by 20 on both sides
0.57735026919*20= \frac{x}{20} *20 \\ 11.5470053838=x \\ 11.5=x
and x = side CA
Next you now know the hypotenuse of the other "triangle"
It's Adjacent and hypotenuse
So that's cos
cos(60)= \frac{x}{11.5} \\ 0.5= \frac{x}{11.5}
multiply by 11.5 on both sides
0.5*11.5= \frac{x}{11.5} * 11.5 \\ 5.75 = x
x= side CB
CB=5.75m
dezoksy [38]3 years ago
4 0
CB is equal to 10m  you can tell this bye the side DC being 20 m and the angle of DC is half of CB so that means that CB has to be 10 m
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6 0
3 years ago
Need help ASAP m<2=92 m<12=74
galben [10]

Answer:

nevermind, i figured it out!

<10 = 92

<8 = 92

<9 = 88

<5 = 106

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yes these are actually the answers, lol

Step-by-step explanation:

6 0
3 years ago
9th grade math help me please and thank you sosomuch
Varvara68 [4.7K]

Answer:

The system is consistent; it has one solution ⇒ D

Step-by-step explanation:

A consistent system of equations has at least one solution

  • The consistent independent system has exactly 1 solution
  • The consistent dependent system has infinitely many solutions

An inconsistent system has no solution

In the system of equations ax + by = c and dx + ey = f, if

  1. a = d, b = e, and c = f, then the system is consistent dependent and has infinitely many solutions
  2. a = d, b = e, and c ≠ f, then the system is inconsistent and has no solution
  3. a ≠ d, and/or b ≠ e, and/or c ≠ f, then the system is consistent independent and has exactly one solution

In the given system of equations

∵ -2y + 2x = 3 ⇒ (1)

∵ -5y + 5x = 12 ⇒ (2)

→ By comparing equations (1) and (2)

∵ -2 ≠ -5

∵ 2 ≠ 5

∵ 3 ≠ 12

→ By using the 3rd rule above

∴ The system is consistent independent and has exactly one solution

∴ The system is consistent; it has one solution

7 0
3 years ago
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Ierofanga [76]

Answer:

Step-by-step explanation:

9.25=\frac{925}{100} \\592 \div9.25=592 \div \frac{925}{100} =\frac{59200}{925}

3 0
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