A segment can have more than one bisector. True False

1 answer:

4 0

<span>Can a Segment have more than one bisector. Yes A segment can have more than one bisector. For every line segment, there is one perpendicular bisector that passes through the midpoint. There are infinitely many bisectors, but only one perpendicular bisector for any segment.</span>

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What is the length of the line?

mamaluj [8]

Hi there!

$\large\boxed{\text{ D. } \sqrt{136}}$

Use the Pythagorean theorem to find the length of the line.

If we draw an imaginary right triangle using the given line as the hypotenuse, we can derive a height of 6 units and a length of 10 units.

Use the Pythagorean theorem equation:

c² = a² + b²

Plug in the height and length:

c² = 6² + 10²

Simplify:

c² = 36 + 100

c² = 136

Take the square root of both sides:

c = √136. The correct answer is D.

8 0

2 years ago

The length of the hypotenuse of a 30-60-90 triangle is 9. What is the perimeter?

denis23 [38]

The perimeter of any figure, is all its sides summed up

now, notice the picture below, using the 30-60-90 rule, that's "x"

now, get the other sides, since you know what "x" is, and sum them up, that's the perimeter

5 0

2 years ago

Read 2 more answers

Volunteers helped clean up 8.2 kg of trash in one neighborhood and 11 1/2 kg in another. They sent 1 1/4 kg to be recycled and t

Ivan

Answer: $18.45\ kg$ or $18\frac{9}{20}\ kg$

Step-by-step explanation:

We can convert from mixed numbers to decimal numbers:

$11\frac{1}{2}\ kg=(11+0.5)\ kg=11.5\ kg\\\\1\frac{1}{4}\ kg=(1+0.25)\ kg=1.25\ kg$

Since they cleaned up 8.2 kilograms of trash in one neighborhood and 11.5 kilograms in another neighborhood, the total trash they cleaned up was:

$Total=8.2\ kg+11.5\ kg\\\\Total=19.7\ kg$

We know that they sent 1.25 kilograms to be recycled. Then, in order to calculate how many kilograms of trash they threw away, we must subtract the total kilograms of trash they cleaned up and the kilograms they sent to be recycled.

Then:

$19.7\ kg-1.25\ kg=18.45\ kg$ or $18\frac{9}{20}\ kg$