Answer:
Option A and Option D are correct
Answer:
<h3>The given statement " The distribution of the sample mean, x-bar, will be normally distributed if the sample is obtained from a population that is normally distributed, regardless of the sample size " is <u>
True. </u></h3>
Step-by-step explanation:
Given statement is " The distribution of the sample mean, x overbar, will be normally distributed if the sample is obtained from a population that is normally distributed, regardless of the sample size".
<h3>To check whether the given statement is true or not :</h3>
- The distribution of the sample mean, x-bar, will be normally distributed if the sample is obtained from a population that is normally distributed, regardless of the sample size is <u>True. </u>
- The standard error of the mean is divided into half, then the sample size must be doubled.
∴ The given statement is true.
Answer:
195 mL of the 90% solution
Step-by-step explanation:
Let the number of mL of 90% mixture = x
Hence, our equation is
780mL × 15% + x mL × 90% = (780mL + x) 30%
117 + 0.9x = 234 + 0.3x
Collect like terms
0.9x - 0.3x = 234 - 117
0.6x = 117
x = 117/0.6
x = 195 mL
Therefore, You will need 195 mL of the 90% solution
Answer:
x = -1 ± √6
Step-by-step explanation:
Lets use the quadratic formula →
So ,
Lets take 2 common from numerator.
Cancelling 2 from numerator & denominator gives
A:
Area: 289 m
Perimeter: 51 m
B:
Area: 4 m
Perimeter: 8 m