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2 years ago

What would be the most logical first step for solving this quadratic equation?

Mathematics

1 answer:

Andru [333]2 years ago

8 0

Answer:

C. Add 8 to both sides

Step-by-step explanation:

This is done in order to equate the equation to zero so that it relates to the general equation.

${ax}^{2} + bx + c = 0$

c is (13 + 8)

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PLEASE HELPP !! :C please I'll give brainly to whoever gets it correct

aalyn [17]

Its A, and both by a factor 1/15

4 0

2 years ago

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Two submarines are underwater. The number - 4,820 represents Submarine A’s position (in feet) relative to the surface. The numbe

GarryVolchara [31]

Answer:

Step-by-step explanation:

Take an easier number. Suppose you owe your mother = 10 dollars and your father 15. Which one is the bigger debt? Isn't it your father.? So how do you represent the two debts.

Father = - 15

Mother = - 10

Which number is bigger? - 10. Remember the question is bigger. You would rather own just 10 dollars.

So which number is "larger"?

Isn't it -4488. If it was money and you owed it, would it be the debt you would rather have than -4820

7 0

2 years ago

Given: 3x + y = 1. Solve for y. O y=-3x + 1 O y=-3x - 1 O y = 3x - 1

Ivan

Answer:

easy

Step-by-step explanation:

subtract 3x both side

3 0

2 years ago

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Find x, and then any unknown angles in the quadrilateral. x= ?

sertanlavr [38]

Answer:

x=65

other angle= 165

Step-by-step explanation:

quadrilaterals always have a total of 360 degrees

because of this you can set up an equation and solve

360=90+40+x+(4x-95)

360=130+5x-95

360=35+5x

325=5x

65=x

plug this in to find missing angle

4(65)-95=165

7 0

3 years ago

How many different twotwo-letter passwords can be formed from the letters

Anna [14]

Answer:

$70$

Step-by-step explanation:

GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.

TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.

SOLUTION:

Total number of different letters $=8$

for two two-letter passwords $4$ different are required.

Number of ways of selecting $4$ different letters from $8$ letters $=^8C_4$

$=\frac{8!}{4!4!}$

$=70$

Hence there are $70$ different two-letter passwords can be formed using $8$ letters.

5 0

3 years ago