Question

How many grams of NO will be produced from 60.0g of NO2 reacted with excess water in the following chemical reaction?

Answer 1

Answer:

Mass = 19.78 g

Explanation:

Given data:

Mass of NO produced = ?

Mass of NO₂ reacted = 60.0 g

Solution:

Chemical equation:

3NO₂(g) + H₂O(l)   →  2HNO₃(g) + NO(g)

Number of moles of NO₂:

Number of moles = mass/molar mass

Number of moles = 60.0 g/ 46 g/mol

Number of moles = 1.3 mol

Now we will compare the moles of NO₂ with NO.

                      NO₂         :           NO

                        3            :            1

                      1.3            :            1/3×1.3 = 0.43 mol

Mass of NO:

Mass = number of moles × molar mass

Mass = 0.43 mol × 46 g/mol

Mass = 19.78 g