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aksik [14]
4 years ago
13

How many grams of NO will be produced from 60.0g of NO2 reacted with excess water in the following chemical reaction?

Chemistry
1 answer:
Lynna [10]4 years ago
6 0

Answer:

Mass = 19.78 g

Explanation:

Given data:

Mass of NO produced = ?

Mass of NO₂ reacted = 60.0 g

Solution:

Chemical equation:

3NO₂(g) + H₂O(l)   →  2HNO₃(g) + NO(g)

Number of moles of NO₂:

Number of moles = mass/molar mass

Number of moles = 60.0 g/ 46 g/mol

Number of moles = 1.3 mol

Now we will compare the moles of NO₂ with NO.

                      NO₂         :           NO

                        3            :            1

                      1.3            :            1/3×1.3 = 0.43 mol

Mass of NO:

Mass = number of moles × molar mass

Mass = 0.43 mol × 46 g/mol

Mass = 19.78 g

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Answer:

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Explanation:

To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.

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Molar Mass (C₃H₈): 44.094 g/mol

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Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)

Molar Mass (CO₂): 44.01 g/mol

250. g C₃H₈         1 mole C₃H₈           3 moles CO₂              44.01 g
------------------  x  ----------------------  x  ----------------------  x  --------------------  =
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= 749 grams CO₂

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