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3 years ago

Which is the best location for storing radioactive wastes?

2 answers:

4 0

Deep geological disposal is widely agreed to be the best solution for final disposal of the most radioactive waste produced.

Geological disposal involves isolating radioactive waste deep inside a suitable rock volume to ensure that no harmful quantities of radioactivity ever reach the surface environment.

Hope this helps :)

Tanzania [10]3 years ago

4 0

Answer:

Ik this is from 2017 but the correct answer is B. I’m chambers carved into the rock of a mountain

Explanation:

I got this answer correct on my quiz!

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Need answer ASAP!!!!

Keith_Richards [23]

Answer:

I am sure it is D or C. have a nice day

6 0

2 years ago

What term is defined as splitting large nuclei into smaller ones

svetoff [14.1K]

Answer:

Nuclear Fission.

Explanation:

This happens when a high-energy particle collides with a radioisotope, which splits into 2 daughter nuclei, several neutrons (which can collide with more radioisotopes to cause a chain reaction); and a lot of energy. That's why nuclear power plants are so good.

5 0

3 years ago

Which piece of equipment would be most useful for measuring the volume of some water?

kicyunya [14]

graduated cylinder is the answer

5 0

3 years ago

Read 2 more answers

you fill a rigid steel container that has a volume of 20 L with nitrogen gas to a final pressure of 2 x 10^4 kpa at 23 Celsius.

garik1379 [7]

Answer:

4.549 kg.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 2 x 10⁴ kPa/101.325 = 197.4 atm).

V is the volume of the gas in L (V = 20.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 23° C + 273 = 296 K).

∴ n = PV/RT = (197.4 atm)(20.0 L)/(0.0821 L.atm/mol.K)(296 K) = 162.5 mol.

To find the mass of N₂ in the cylinder, we can use the relation:

mass of N₂ = (no. of moles of N₂)*(molar mass of N₂) = (162.5 mol)*(28.0 g/mol) = 4549 g = 4.549 kg.

3 0

3 years ago

Copper(II) sulfide is formed when copper and sulfur are heated together. In this reaction,

storchak [24]

Answer:

The mass of copper(II) sulfide formed is:

= 81.24 g

Explanation:

The Balanced chemical equation for this reaction is :

$Cu(s) + S\rightarrow CuS$

given mass= 54 g

Molar mass of Cu = 63.55 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$moles=\frac{54}{63.55}$

Moles of Cu = 0.8497 mol

Given mass = 42 g

Molar mass of S = 32.06 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$moles=\frac{42}{32.06}$

Moles of S = 1.31 mol

Limiting Reagent : The reagent which is present in less amount and consumed in a reaction

First find the limiting reagent :

$Cu + S\rightarrow CuS$

1 mol of Cu require = 1 mol of S

0.8497 mol of Cu should require = 1 x 0.8497 mol

= 0.8497 mol of S

S present in the reaction Medium = 1.31 mol

S Required = 0.8497 mol

S is present in excess and Cu is limiting reagent

All Cu is consumed in the reaction

Amount Cu will decide the amount of CuS formed

$Cu + S\rightarrow CuS$

1 mole of Cu gives = 1 mole of Copper sulfide

0.8497 mol of Cu = 1 x 0.8497 mole of Copper sulfide

= 0.8497

Molar mass of CuS = 95.611 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$0.8497 = \frac{given\ mass}{95.611}$

Mass of CuS = 0.8497 x 95.611

= 81.24 g

3 0

3 years ago