No, unless the slime or paper is wet.
Density = mass divided by volume
Density = 8.2 divided by 24.5
Density = 0.33g/cm3
Here you go! There are 0.9307 moles in 123.0 g of the compound. I solved this by using a fence post method. I calculated the number of grams in one mol of (NH4)2 SO4 and got 132.16.
I did this by finding the atomic mass of each element on the periodic table (my work is in the color blue for this step)
After that, i divided the given mass by the mass of one mol of the compound.
The answer is 0.9307 moles!! I hope this helped you! :))
Answer:
158.2598
Explanation:
158.2598 moles are in 78.8 g of potassium sulfite
CARRY ON LEARNING
Since the Mg is in excess, therefore HCl will be fully
consumed in the reaction.
The first step is to find the amount of HCl in mol
Let N (HCl) = amount
of HCl in mol
N (HCl) = (6 mol HCL/L solution) *( 125 mL ) * (1 L/1000 mL)
= 0.75 mol of HCl
Through stoichiometry
N (H2) = 0.75 mol HCl * (1 mol H2/ 2 mol of HCl)
N(H2) = 0.375 mol H2
Since we are asked
for the number of grams of H2 (mass), we multiply this with the molar mass of hydrogen
M (H2) = 0.375 mol H2 ( 2 g H2 / 1 mol H2)
M (H2) = 0.75 g H2