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3 years ago

| x | = 6 Solve for x

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

1 x 6= 6 x 1= 6

Ronch [10]3 years ago

3 0

Answer:

x = 6, -6

Step-by-step explanation:

The absolute value of a number is its distance from 0 on the number line. To find the absolute value of a number through an equation, write two equations: one where the side without the variable is positive, and one where the side without the variable is negative. In this case, it would look like this:

| x | = 6 and | x | = -6

Then, solve whatever is inside the absolute value and take out the absolute value lines. In this equation, we don't need to solve anything, so we can just take out the lines. So, we'll end up with:

x = 6 and x = -6

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Solve 3(2x-5)-4x+8=-1

777dan777 [17]

Answer:

Step-by-step explanation:

Step 1:

3 ( 2x - 5 ) - 4x + 8 = - 1

Step 2:

5x - 15 - 4x + 8 = - 1

Step 3:

x - 15 + 8 = - 1

Step 4:

x - 7 = - 1

Answer:

x = 6

Hope This Helps :)

7 0

3 years ago

Which choice is equivalent to √10*√5? A. 5√2 B. 25√2 C. 5√10 D. 2√5

DanielleElmas [232]

Answer: $5\sqrt{2}$

Step-by-step explanation:

$\sqrt{10} *\sqrt{5} =\sqrt{50} =\sqrt{2*5*5} =5\sqrt{2}$

3 0

3 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

A chord of a circle is a line segment connecting any point on the circle to the center of the circle.

andrezito [222]

Answer:

FALSE

Step-by-step explanation:

A chord of a circle is a line segment that connects two points on the circle.

5 0

3 years ago

Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12

Montano1993 [528]

$0.05p-0.02(5-2p)=0.05(p-2)-0.12$

$0.05p-0.02(5-2p)=0.05(p-2)-0.12:p$

$
0.05p-0.1+0.04p=0.05p-0.1-0.12
 
$ $|Expand \ the \ equation|$

$0.09p-0.1=0.05p-0.1-0.12
 
$

$0.09p-0.1=0.05p-0.22$

$
0.09p-0.1-0.05p=-0.22
 

$ $|Subtract \ 0.05p \ from \ both \ sides|$

$
0.04p-0.1=-0.22
 
$

$
0.04p=-0.22+0.1
 
$ $|Add \ 0.1 \ to \ both \ sides|$

$
0.04p=-0.12
 
$

$0.04p/0.04=-0.12/0.04
$ $|Divide \ both \ sides \ by \ 0.04|$

$p=-3$

$\star \ Hence \ Solved$

8 0

3 years ago