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Romashka-Z-Leto [24]
3 years ago
15

How many terms are in the expansion (a+b)19

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

There are 2 ters because you would distribute the 19 to the a and the b to make it 19a + 19b, which has 2 terms

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Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
the axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2. what are the coordinates of the vertex of the graph?
Alenkasestr [34]
Hello : 
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b 
f(x) x²+4x+4+b=  x² +4x-5 
 4+b= -5 
b = -9
the vertex is : (2 , -9)
4 0
3 years ago
Read 2 more answers
What is 35 liters in milliliters
Evgesh-ka [11]
The answer is 35,000
6 0
3 years ago
In 2000, the population of Big Springs was 13 thousand. Use the given doubling
trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is  t =0.

Formula:

A= A_0e^{rt}

Where,

A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year

for doubling time,

r = \frac{log (2)}{t} \\

r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007

Given value:

A = A_0e^{rt} \\\\

A_0 = 13000

t= 40 \ years

when year is 2000, t=0 so, year is 2100 year as t = 100.

A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4

7 0
3 years ago
1. Find the mean for 2, 5, 9, 4
Reil [10]

Answer:

Answer 1. 5     Answer 2. 60   Answer 3. 37

Step-by-step explanation:

6 0
3 years ago
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