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max2010maxim [7]
3 years ago
10

Ms Steward is training for an IronMan Competition. She is determined to shatter every record ever known. She bikes, runs and swi

ms. In two weeks she bikes 75.4 miles 8 times. She runs 22.4 miles three days and 27.5 miles 5 days. She swam 15 miles for 7 days consecutively. How many miles did Ms. Steward train in all?
Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

912.9 miles total

Step-by-step explanation:

75.4 miles biking x 8 times =  603.2 miles in biking

22.4 miles running x 3 days =  67.2 miles in running

27.5 miles running x 5 days =  137.5 miles running (2nd)

15 miles swimming x 7 days =  105 miles swimming

603.2+67.2+137.5+105 =

912.9 miles total

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Write an expression<br> for: "the quotient of<br> a number and 7<br> increased by 10"
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A personnel director in a particular state claims that the mean annual income is the same in one of the​ state's counties​ (Coun
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Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>(a) Identify the claim and state  H0  and  Ha. </em>

<em> Which is the correct claim​ below?</em>

<em>(b) Find the critical​ value(s) and identify the rejection​ region(s). </em>

<em> Enter the critical​ value(s) below.</em>

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950

The degrees of freedom are:

df=n_a+n_b-2=18+8-2=24

Then, the test statistic is:

t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

5 0
3 years ago
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