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Valentin [98]
3 years ago
6

What adds to -8 and multiplies to -20

Mathematics
2 answers:
slamgirl [31]3 years ago
4 0
I assume that you are talking about 2 integers
one of the integers must be negative while the other is positive
we can list integer pairs that multiply to -20:
-20 1
20 -1
-10 2
10 -2
5 -4
-5 4
now the only pair that when you add them together equals -8 is -10 and 2, so
-10 and 2 add to -8 and multiply to -20
swat323 years ago
4 0
My answer is <span>-10 and 2 add to -8 and multiply to -20</span>
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Hw 43 special right triangles
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Answer:


Step-by-step explanation:

Use the fact that sin 30 =0.5 and cos 30 = sqrt 3/2

we have answers as

8. u=16 and v = 8\sqrt{3}

9) y=5 and x=5\sqrt{3}

10) tan 30 =\frac{1}{\sqrt{3} }

So y=4\sqrt{3}

x=8\sqrt{3}


11) a=22 and b=11

12) b=1.5 and a=1.5\sqrt{3}

13) y=20\sqrt{3}

and x=10



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3 years ago
Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y
koban [17]

\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}

Substituting this into the other ODE gives

-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0

Since x(t)=-\dfrac14y'(t), it follows that x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16. The ODE in y has characteristic equation

r^2-16=0

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\implies C_1=\dfrac12,C_2=\dfrac92

So we have

\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}

Take the derivative and multiply it by -1/4 to get the solution for x(t):

-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}

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3 years ago
Solve each equation <br><br> r - 5 1/6 = 10 <br><br> please help me Thank youuu!
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3 years ago
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