The area of the resulting two-dimensional cross section with the dimensions shown in the figure can be determined by simply using the formula for the area of a rectangle.
Given:
Length = 12 mm
Width = 7 mm
Area = L x W
Area = 12 mm x 7 mm
Area = 84 mm^2
Hmmm I'd do synthetic division here.
you set it up as
n | coefficient of first, second, third,...so on|
where n is from x-n, a factor of my polynomial. I realize that's a bad explanation so I'll show it with this one
so, setting this up, I have x-8 as my potential factor, so n would equal 8.
8 |
now list the coefficients of all the terms in your polynomial.
8 | 1... -3.... -31.... -72 |
you drop down the first coefficient shown, and multiply it by n, and put that under the second coeffiecient, then add.
8 | 1 ...-3 ....-31 ....-72|
......1 ..+ 8 (1)
8 + -3 is 5, so multiply 5 by 8 and put that under the next coeffient, add, and so on.
8 | 1 ......-3..... -31..... -72|
......1 .....+ 8... +40 ...+72
...............5 ........9........ 0
if I get a remainder of 0, or a 0 after you've done everything (which we have) then whatever x-n you have IS a factor of your polynomial. so, x-8 is a fsctor. :) hope that helps!
EDIT: sorry about the periods haha. just trying to make it easier to see.
Answer:
Step-by-step explanation:
The ratio that will determine the size of x, y, z is 9 / 12 That comes about because 9 value is parallel to the 12 value when both are extended in either direction
x
9/12 = x / 22 Cross multiply
12x = 9 * 22
12x = 198 Divide by 12 on both sides
x = 198/12
x = 16.5
y
y and 24 are related because they are parallel
9/12 = y/24 Cross multiply
12y = 9 * 24
12y = 216
y = 216 / 12
y = 18
z
See the solution for x. z = x