Perpendicular lines have slopes that multiply to -1
get into y=mx+b form
minus 15x both sides and divide by -5
y=3x-7/5
slope is 3
3 times what=-1?
what=-1/3
so the slope is -1/3
so
y=-1/3x+b
we use the point (0,-4)
x=0 and y=-4
-4=-1/3(0)+b
-4=b
y=(-1/3)x-4 is da equation
South west
Shifting 4 units left (decreasing in x-axis by 4 units)
Shifting 5 units down (decreasing in y-axis by 5 units)
Apply to every vertices coordinates(x - 4, y - 5)
New coordinates
A(-2, -1)
B(-1, -4)
C(1,0)
Answer:
The equation of a line, having inclination 120° with positive direction of x-axis, .of x-axis, which is at a distance of 3 units from the origin is. 1. See answer ... where α is the angle with the positive X-axis, made by the perpendicular line drawn Now, from equation the equation of the straight line will be.
Step-by-step explanation:
Hey! Good Morning! (if its morning for you) Easy way to figure these things out is to just graph them an take a look. Since we know this is a parallelogram, we can use the basic rules of them to know for sure where that one last point is. (Or we can use the first way, your choice) So just by graphing those points and looking at the incomplete stricter it created,
We can know the last point lies at (0, 2) (I put this spaced so you don't have to read my entire message lol) Hope this helps and good luck!
b is the correct answer u got it