3 years ago

Solve for X 3 (x+1)=9

Mathematics

1 answer:

gogolik [260]3 years ago

6 0

Answer:

x=2

Step-by-step explanation:

3(x+1)=9

3x+3=9

3x=6

x=2

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stellarik [79]

Answer:

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2 years ago

If n^3=x and n^4=20x , where n>0, what is the value of x?

Natali5045456 [20]

Step-by-step explanation:

∠2 and ∠7 are alternate exterior angles so they are equal.

So you can create the equation

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3 years ago

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3 years ago

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mestny [16]

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3 years ago

Read 2 more answers

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

nalin [4]

For each $1\le i\le n$ , $E[X_i]=0$ , so that

$\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0$

Meanwhile,

$\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]$

Each of the $X_i$ have PDF

$f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}$

for $x\in\Bbb R$ . From this we get

$E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}$

$\implies E[Y_2]=n\sqrt{\dfrac2\pi}$

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2 years ago