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pantera1 [17]
3 years ago
8

A scale measures weight to the nearest 0.1 pounds. Which is the most appropriate way to report weight using this scale?

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0
The question is kind of vague in my opinion.

the best measurement to report with the scale in my opinion would be tens of pounds. my reasoning is because the decimal place would still prove importance with numbers under one hundred. above one hundred pounds and the decimal place becomes kind of pointless. 

I hope I answered your question. though i'm sorry if i didn't 
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Factor Completely: 12x2 + 22x + 6 A) (2x+ 3)(6x + 2) B) 6(x + 1)(2x + 1) C) 2(2x + 3)(3x + 1) D) 2(2x + 1)(3x + 3)
tia_tia [17]

Answer:

C) 2 (2x + 3) (3x + 1)

Step-by-step explanation:

12x² + 22x + 6

2 ( 6x² + 11x + 3 )

2 [ 6x² + 9x + 2x + 3 ]

2 [ 3x ( 2x + 3 ) + 1 ( 2x + 3 ) ]

2 ( 2x + 3 ) ( 3x + 1 )  ⇒ C

7 0
3 years ago
NEED MATH HELP NOW. Please solve for x-intercept.
Lelechka [254]

Answer:

(1, 0) and (3, 0)

Step-by-step explanation:

y=2x²-8x+6

x- intercept when y=0

  • 2x²-8x+6=0
  • x²-4x+4=1
  • (x-2)²=1
  • x-2=1 ⇒ x= 3
  • x-2= -1 ⇒ x= 1
5 0
3 years ago
Explain the relationship between the number of painters and sculptors enrolled in the art schools?
nasty-shy [4]

The relationship between the number of painters and sculptors enrolled in the art school can be considered a direct variation.

<h3>Direct variation</h3>

A direct variation as implied above means, the linear relationship between the number of painters and sculptors enrolled in the art school are directly proportional.

  • In essence, as the number of sculptors in the art schools increase, the number of painters increases too. This is because, more painters are needed to paint increasing work volume of the sculptors.

Read more on direct proportion;

brainly.com/question/1266676

6 0
3 years ago
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken
Leviafan [203]

Answer:

a. H0:μ1≥μ2

Ha:μ1<μ2

b. t=-3.076

c. Rejection region=[tcalculated<−1.717]

Reject H0

Step-by-step explanation:

a)

As the score for group 1 is lower than group 2,

Null hypothesis: H0:μ1≥μ2

Alternative hypothesis: H1:μ1<μ2

b) t test statistic for equal variances

t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}

t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}

t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]

t=-3.076

c. α=0.05, df=22

t(0.05,22)=-1.717

The rejection region is t calculated<t critical value

t<-1.717

We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.

7 0
3 years ago
So right now i'm doing "solving Inequalities" i need help with this question<br> 3v-12&gt;5v+10
LenKa [72]

Answer:

v < -11

Step-by-step explanation:

  1. Combine like terms: 3v - 5v > 12 + 10
  2. Simplify: -2v > 22
  3. Divide each side by -2 to cancel out the -2 next to v. It should now look like this: v < -11

I hope this helps!

7 0
3 years ago
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