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amid [387]
3 years ago
15

Triangles ABC and DEF are similar.

Mathematics
1 answer:
vivado [14]3 years ago
3 0
All I can really remember is find the scale factor and divide it by the segment
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(WILL GIVE BRAINLIEST) I NEED HELP ASAP!!!
aleksandr82 [10.1K]

Answer:

which ones do you need answered? all of them? want to help

Step-by-step explanation:

4 0
3 years ago
Which inequality is represented by the graph?
PSYCHO15rus [73]

Answer:

<h2>NONE OF THEM</h2>

Step-by-step explanation:

From the graph,

y and x intercepts are (0,-3) and approximately (1.9,0) respectively

for A, C and D : y=53x-3

x intercept the value of y=0, and y intercept x=0.

x and y intercepts are (\frac{3}{53},0 ) and approximately (0,-3) respectively

for B: y=35x-5

 x and y intercepts are (\frac{3}{35},0 ) and approximately (0,-3) respectively

Therefore x and y intercepts for the lines y\leq 53x-3,y>53x-3, y and y they are not equal to the x and y intercepts of the given graph

3 0
3 years ago
I need help asappppppppp
Jobisdone [24]

Answer:

I'm not sure but I think is 31.4

Step-by-step explanation:

multiply 15.70 twice

5 0
3 years ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
There are 7052 boys and adults at carnival.
Basile [38]

Answer:

There are 6,296 children at the carnival

Step-by-step explanation:

The number of each group of people can be expressed as;

Number of boys (b)+number of adults (a)=7,052

b+a=7,052....equation 1

Number of girls (g)=Number of adults (a)-756

g=a-756....equation 2

But Number of girls (g)=number of boys (b)

Replacing the value of b in equation 1 with that of g in equation 2;

(a-756)+a=7,052

a+a=7,052+756

2 a=7,808

a=7,808/2

a=3,904

Replace the value of a in equation 2 with 3,904

g=3,904-756

g=3,148

But since g=b

g=b=3,148

b=3,148

Total number of children=Total number of boys (b)+total number of girls (g)

Total number of children=b+g

where;

b=3,148

g=3,148

replacing;

Total number of children=(3,148+3,148)=6,296

There are 6,296 children at the carnival

6 0
3 years ago
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