Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Answer:
91
Step-by-step explanation:
Substitute 4 in place of x
f(4)=20*4+11
f(4)=80+11
f(4)=91
<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,

The zeros of the polynomials are,







Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
-4:2000
-2:1000
-1:500
Hope this helped☺☺