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lutik1710 [3]
3 years ago
15

I need help with this

Mathematics
2 answers:
Harrizon [31]3 years ago
4 0

105 \div 8.7

ivolga24 [154]3 years ago
4 0

Answer:

105/8.7.............

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The point (-3,3) lies on a circle. What is the length of the radius of this circle if the center is located at (10,6) ?
Amiraneli [1.4K]
The radius is from center to point on a circle. 
So your task is  count distance between two points: S(10,6) and A(-3,3). 
Distance between two points A(x1, y1) and B(x2, y2)  count from this formula:
|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ \hbox{So:} \\ \\ r=|SA|=\sqrt{(-3-10)^2+(3-6)^2}=\sqrt{(-13)^2+(-3)^2}=\sqrt{169+9}= \\ r= \sqrt{178}
5 0
3 years ago
Read 2 more answers
A=8, b=5, C=90 degree; Find c, A, and B<br><br> This is for the law of sine and cosine
brilliants [131]

Answer:

• c = √89 ≈ 9.434

• A = arcsin(8/√89) ≈ 57.995°

• B = arcsin(5/√89) ≈ 32.005°

Step-by-step explanation:

By the law of cosines, ...

c² = a² + b² -2ab·cos(C)

Since c=90°, cos(C) = 0 and this reduces to the Pythagorean theorem for this right triangle.

c = √(8² +5²) = √89 ≈ 9.434

Then by the law of sines (or the definition of the sine of an angle), ...

sin(A) = a/c·sin(C) = a/c = 8/√89

A = arcsin(8/√89) ≈ 57.995°

sin(B) = b/c·sin(C) = b/c = 5/√89

B = arcsin(5/√89) ≈ 32.005°

6 0
3 years ago
It takes one week for a crew of workers to pave 3/5 kilometer of a road. At that rate, how long will it take to pave 1 kilometer
Flauer [41]

Answer:

1.67 weeks

Step-by-step explanation:

Let X= time it will take to pave 1 kilometer?

1 week=3/5 kilometer

X week =1 kilometer

Cross multiply

3/5 X= 1

3X= 5

X= 5/3

1.67 weeks

8 0
3 years ago
The equation, y = 12841(1.01)x , represents the average cost of an education at a private college, after 1990. What is the avera
____ [38]
The average cost in 1990 is <span>$12,841.</span>
3 0
3 years ago
Read 2 more answers
Simiplify without using absolute value bars, Solve for |x +7| for x&gt;=7
Pavlova-9 [17]

9514 1404 393

Answer:

  x +7

Step-by-step explanation:

The argument of the absolute value function is positive for any x > -7. The required domain is a subset of that, so the absolute value function does not change its argument.

  |x+7| for x ≥ 7 is x +7

5 0
3 years ago
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