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Zanzabum
3 years ago
7

Tyler simplified the expression x Superscript negative 3 Baseline y Superscript negative 9. His procedure is shown below.

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

y^{-9}\neq \dfrac{1}{y^{-9}}

Step-by-step explanation:

Tyler simplified the expression: x^{-3}y^{-9}  as shown below:

x^{-3}y^{-9}=\dfrac{1}{x^3}X \dfrac{1}{y^{-9}}=\dfrac{1}{x^3y^{-9}}

We notice that in Tyler's work:

y^{-9}= \dfrac{1}{y^{-9}}

Whereas, the correct form would have been:

y^{-9}= \dfrac{1}{y^{9}}

Making our solution:

x^{-3}y^{-9}=\dfrac{1}{x^3}X \dfrac{1}{y^{9}}=\dfrac{1}{x^3y^{9}}

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24 times 4 tons 2 pounds
Iteru [2.4K]
Ayy, so your question is kinda weirdly worded. But I think your asking what is 24 multiplied by 4 tons and 2 pounds.

Well, 2 pounds is equal to 0.00090718 tons.
There is a converter here: https://www.bing.com/search?q=pounds+to+tons&qs=AS&pq=pounds+to+tons&sc=8-14&sp=1&cvid=7BC591B75A8B4......

But now we have 0.00090718 tons as well as 4 tons. Add those together and you get 4.00090718. Now, multiply this by 24. You get: 96.02177232.


7 0
3 years ago
with Judy jogging north and Jackie jogging west (on straight roads). When Jackie is 1 mile farther fro m the intersection than J
miskamm [114]
Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.

We convert the given information to equations, step by step.

Point 1: When Jackie is 1 mile farther from the intersection than Judy.

This means y is 1 mile more than x.

So,

y = 1 + x

Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection. 

Distance between is x+ y.

So, x+y is 2 miles more than y.

x+y = y + 2
⇒
x = 2

From point 1 we have:

y = 1 + x = 1+ 2 = 3

So,

Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
4 0
3 years ago
Write 15+45 as a product of two factors using the gcf and the distributive property
valkas [14]

Answer:

15(1 + 3)

Step-by-step explanation:

15 written in its prime factors is 3 × 5 (15 × 1)

45 written in its prime factors 3 × 3 × 5 (15 × 3)

The greatest common factor is 15: 15 × 1 = 15 and 15 × 3 is 45

∴ 15 + 45 = 15(1 + 3)

Hope this helps! Make me brainiest, lol it's fine if you don't. : )

5 0
2 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
Solve - 2/5x is less than or equal to 20
sashaice [31]

Answer:

x is less than or equal to 0

Step-by-step explanation:

- you need to multiply both sides of the inequality by 5/2

- then you reduce the numbers with the greatest common factor 5

- then you reduce the numbers with the greatest common factor 2

- any expression multiplied by 0 equals 0

- so you get x is less than or equal to 0

^^^ hope this helps! :)

8 0
3 years ago
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