Answer:
<h3>AB ≈ 70m</h3>
Step-by-step explanation:
Check the attachment for the diagram.
You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;
tan 35° = opposite/adjacent
tan 35° = AB/BC
tan 35° = AB/100
AB = 100tan35°
AB = 100 * 0.7002
AB = 70.02m
Hence the distance across a lake between A and B is approximately 70m
Answer:
-4.25
Step-by-step explanation:
The given number is 4.25 and we have to find the opposite of this number.
Opposite of a number is also known as additive inverse and it is defined as "if the sum of two numbers is zero then two numbers are opposite or additive inverse of each other"
For example, if x is a number then its opposite is -x.
and hence, x + (-x) = 0
Using this fact, we can conclude that the opposite of 4.25 is -4.25 because
4.25 + (-4.25)
= 4.25 - 4.25
=0
Answer: 7
Step-by-step explanation:
18 + 46 = 64
See image
6s into 6 = 1
6s into 4 = 0 - carry the 4 over to the next space
6s into 40 = 6 remainder 4 - carry the 4
6s into 40 = 6 remainder 4 - carry the 4
4 will become repeatedly carried (an infinite number of times) so we call it a recurring number. This can be shown by a number (in this case 6) with a dot above it.
(18 + 46)/6 = 10.666... or 10.67
Answe and Step-by-step explanation:
Looking at the question the way it was asked, it is easy because it said they have been labelled, so you don't have to stress yourself. Although, if what is intended is, the labelling got wrong along the way and how do you identify the correct one? Then this is what to do:
Go to the one labelled RB. Since I'm assuming that the labelling got wrong, if you pick a red, it means what we have should be a RR and if we picked a black, it means what we have is a BB and we can't have a RB because it was labelled wrongly.
Let's assume he saw a red,
We know that the BB box was labelled wrongly, and we already determined that the box with RB is a RR. Therefore, the box BB can never be RR(because we've seen it already) and it's certainly not BB (due to the fact that they were labelled wrongly). So we have only one option left which is it being RB and whatever we have left will be BB.
If we assume what was picked from the wrongly labelled RB is black.
We know that the RR box was labelled wrongly, and we already determined that the box with RB is a BB. Therefore, the box RR can never be BB and it's certainly not RR (due to the fact that they were labelled wrongly). So we have only one option left which is it being RB and whatever we have left will be RR.
