Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer: B) one
This one point is point U since it is on line segment CD. In contrast, a point like point E is not on line CD, so E is not collinear with C and D.
Answer:
2x-6<-18
Step-by-step explanation:
First side is = x
Second side is = 3x-3
Third side is = 44x - 66
Perimeter = Sum of sides
P = x + 3x + 44x -66 -3
P = 48x - 69
Answer:
11/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(55-22)/(15-6)
m=33/9
simplify
m=11/3