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wariber [46]
4 years ago
6

diana and charles shared a sum of money in the ration 3:5 respectively. Charles received 240 what was dianas share​

Mathematics
1 answer:
Dmitrij [34]4 years ago
4 0

Answer:

144

Step-by-step explanation:

Take Charles share and divide it by 5 = 48

Take 48×3=144

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True or False: If we have an integer primal solution with cost C and a fractional dual solution with cost at least C/2, the size
maria [59]

Answer:

True

Step-by-step explanation:

The size of the vertex cover is atleast twice the size of the maximum edge. Vertex must contain atleast one vertex from the matched edge. Vertex are never the strong dual solutions of each other.

3 0
3 years ago
What is m∠Q? Round only your final answer to the nearest tenth. 24.1º 30.8º 59.2º 125.1º
Shtirlitz [24]

The measure of the angle m∠Q is 30.8 degree after applying the law of cosine.

<h3>What is the triangle?</h3>

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

Let's suppose the angle m∠Q is A

So applying law of cosine:

\rm 40^2 = 64^2+32^2-2(64)(32) \ cosA

CosA = 0.859

A = 30.75 ≈ 30.8 degree

Thus, the measure of the angle m∠Q is 30.8 degree after applying the law of cosine.

Learn more about the triangle here:

brainly.com/question/25813512

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5 0
2 years ago
What is 3.2 x 10^-4 m/h in centimeters per second?
Iteru [2.4K]
1m=100cm\\h=3600s\\\\3.2\times10^{-4}\ m/h=3.2\times10^{-4}\times\frac{100}{3600}\ cm/s\\\\=3.2\times10^{-4}\times\frac{1}{36}\ m/s=\frac{3.2}{36}\times10^{-4}\ m/s\\\\=0.888...\times10^{-4}\ m/s=\boxed{8.889\times10^{-5}\ m/s}\\\\Answer:\boxed{b)}
4 0
3 years ago
Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.
Vladimir [108]
\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt
\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k

Given \mathbf r(1)=\mathbf i+\mathbf j, we have

\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12

so that the particular solution is

\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k
8 0
3 years ago
Find the 65th term of a arithmetic sequence -10,-8,-6,-4......
Masja [62]
-69 is the answer i think
8 0
3 years ago
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