Please help, this is for 8th grade math.
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1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:
1) Value of the functions as x increases.
Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1, the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.
While in the graph you see that the function q has a horizontal asymptote that shows that the limit of q (x) when x → ∞ is - 4.
Then, the first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) y - intercepts.
i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2
ii) The y-intercept of q(x) is read in the graph. It is - 3.
Then the answer is that the y-intercept of the function p is greater than the y-intercept of the function q.
1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:
1) Value of the functions as x increases.
Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1, the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.
While in the graph you see that the function q has a horizontal asymptote that shows that the limit of q (x) when x → ∞ is - 4.
Then, the first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) y - intercepts.
i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2
ii) The y-intercept of q(x) is read in the graph. It is - 3.
Then the answer is that the y-intercept of the function p is greater than the y-intercept of the function q.
If 
is conservative, then there is a scalar function 
such that
Setting the first components equal to one another, we can integrate both sides to find
Differentiating both sides with respect to
gives
so that
By the fundamental theorem of calculus, we have that
Setting the first components equal to one another, we can integrate both sides to find
Differentiating both sides with respect to
so that
By the fundamental theorem of calculus, we have that